• 齐次坐标得到非齐次坐标


    李群 S E ( 3 ) SE(3) SE(3)
    T ∈ R 4 × 4 T \in \mathbb{R}^{4 \times 4} TR4×4
    T = [ R t 0 T 1 ] = [ a b c j d e f k g h i l 0 0 0 1 ] T =

    [Rt0T1]" role="presentation" style="position: relative;">[Rt0T1]
    =
    [abcjdefkghil0001]" role="presentation" style="position: relative;">[abcjdefkghil0001]
    T=[R0Tt1]= adg0beh0cfi0jkl1
    一个三维齐次坐标 P P P
    P = [ v 1 v 2 v 3 1 ] P =
    [v1v2v31]" role="presentation" style="position: relative;">[v1v2v31]
    P= v1v2v31

    T P = [ a v 1 + b v 2 + c v 3 + j d v 1 + e v 2 + f v 3 + k g v 1 + h v 2 + i v 3 + l 1 ] TP=
    [av1+bv2+cv3+jdv1+ev2+fv3+kgv1+hv2+iv3+l1]" role="presentation" style="position: relative;">[av1+bv2+cv3+jdv1+ev2+fv3+kgv1+hv2+iv3+l1]
    TP= av1+bv2+cv3+jdv1+ev2+fv3+kgv1+hv2+iv3+l1

    T P u n _ h o m o g e n e o u s = [ a v 1 + b v 2 + c v 3 + j d v 1 + e v 2 + f v 3 + k g v 1 + h v 2 + i v 3 + l ] TP_{un\_homogeneous}=
    [av1+bv2+cv3+jdv1+ev2+fv3+kgv1+hv2+iv3+l]" role="presentation" style="position: relative;">[av1+bv2+cv3+jdv1+ev2+fv3+kgv1+hv2+iv3+l]
    TPun_homogeneous= av1+bv2+cv3+jdv1+ev2+fv3+kgv1+hv2+iv3+l

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  • 原文地址:https://blog.csdn.net/OrdinaryMatthew/article/details/126023489