1050 String Subtraction
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 104. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
For each test case, print S1−S2 in one line.
- They are students.
- aeiou
Thy r stdnts.
总结:这道题还是很简单的,用一个ascii数组标记s2出现过的字符,然后遍历s1字符串,遇到标记过的字符就不打印,反之则打印
- #include
- using namespace std;
-
- int main(){
- string a,b;
- int ascii[128]={0};
- getline(cin,a);
- getline(cin,b);
-
- for(auto c:b) ascii[c]=1;
-
- for(auto c:a){
- if(ascii[c]) continue;
- printf("%c",c);
- }
-
- return 0;
- }
好好学习,天天向上!
我要考研!