csv 过滤及汇总计算

【问题】

In Bookings.csv file each line contains a name, surname, roomtype, check-in date, check-out date separated by semicolons.

Name;Surname;roomtype1.2;2015-03-24;2015-03-26  
Paul;Smith;roomtype1.1;2015-03-21;2015-03-23  
Romas;Babajus;roomtype2.1;2015-03-26;2015-03-28  
Bob;Alfredo;roomtype3.1;2015-03-24;2015-03-26  
Edvard;Jogn;roomtype2.2.;2015-03-04;2015-03-25  
Jonas;Amberto;roomtype3.2;2015-03-20;2015-03-23 

in roomtype1.* , roomtype2.* , roomtype3.* the “*” indicates a room that is considered to be roomtype1.

When there’s a new booking for roomtype1 the program should find the check-out dates of rooms which are roomtype1 (roomtype1.1 and roomtype1.2) and compare each check-out date in order find a room that has the closest check-out date to the new booking date.

So far a was only able to read the whole dates stored in Bookings.csv without knowing to which roomtype those dates belong.

How would you suggest to read only roomtype1 check-out dates from a csv file? Would it be the best way to use a two-dimensional array and loop the file?

So far my code looks like this if that helps.

publicclassBookings{
staticlongdifv;
publicstaticvoidmain(String\[\] args) throws Exception{
SimpleDateFormatft = newSimpleDateFormat("yyyy-MM-dd");
DatecheckIn = null;
DatecheckOut = null;
Datetest = ft.parse("2015-03-30");
StringfileName = "Bookings.csv";
Filefile = newFile(fileName);
try{
ScannerinputStream = newScanner(file);
while(inputStream.hasNext()) {
Stringdata = inputStream.next();
String\[\] values = data.split(";");
checkIn = ft.parse(values\[3\]);
checkOut = ft.parse(values\[4\]); 
// System.out.println("Check in date");
// System.out.println(checkIn);
// System.out.println("Check out date");
// System.out.println(checkOut);
}
 
inputStream.close();
//interval(checkOut, test, TimeUnit.HOURS);
// System.out.println("the difv is " + difv);
// if (checkOut.compareTo(test) <= 0) { // or equal
// System.out.println("Date1 is after or equal to Date2");
// } else if (checkOut.compareTo(test) < 0) {
// System.out.println("Date1 is before Date2");
// } else if (checkOut.compareTo(test) == 0) {
// System.out.println("Date1 is equal to Date2");
// } else {
// System.out.println("How to get here?");
// 
// }
} catch(FileNotFoundExceptione) {
e.printStackTrace();
}
}
publicstaticlonginterval(DatecheckOut, Datetest, TimeUnittimeunit) {
longdiff = test.getTime() - checkOut.getTime();
difv = timeunit.convert(diff,TimeUnit.MILLISECONDS);
returndifv;
}
}

Thank you in advance for your help!

【回答】

本问题需要进行字段查询、求最大值，这些都是结构化数据的基本运算，但 JAVA 缺乏相关的类库，实现过程复杂，代码可读性差。这种情况下可以用 SPL 辅助实现，代码更直观易懂：

A1: 读入文件，分割符是分号，将第一行读为字段名。

A2: 查询 roomtype 字段，argtype 是查询参数，* 是通配符。

A3: 计算最大值，排序规则是 check-out 字段和输入参数 argDate 的间隔。

集算器提供了易于集成的 JDBC 接口，结合集算器可以大大简化 JAVA 中的结构化计算，详细可参考：

【Java 如何调用 SPL 脚本】

【集算器协助 java 处理结构化文本】