【PAT（甲级）】1058 A+B in Hogwarts

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

解题思路：

给出A和B两个的Galleon.Sickle.Knut要求我们对他们进行不同进制的相加（，17，29）。题目默认Galleon的相加不会超过要求值，所以只要全部读入再相加，进制的话就（%它对应的进制数即可）。

代码：

#include
using namespace std;
int main(){
	int G,S,K,G1,S1,K1;
	cin>>G;getchar();
	cin>>S;getchar();
	cin>>K;getchar();
	cin>>G1;getchar();
	cin>>S1;getchar();
	cin>>K1;getchar();
	
	int rG,rS,rK;
	rK = (K+K1)%29;
	rS = (S+S1+(K+K1)/29)%17;//rK对rS是否有进位只要整除就可以看出 
	rG = (G+G1+(S+S1+(K+K1)/29)/17);
	cout<"."<"."<
	return 0;
}