485. 最大连续 1 的个数(javascript)485. Max Consecutive Ones

给定一个二进制数组 nums ， 计算其中最大连续 1 的个数。
Given a binary array nums, return the maximum number of consecutive 1’s in the array.

示例 1：

输入：nums = [1,1,0,1,1,1]
输出：3
解释：开头的两位和最后的三位都是连续 1 ，所以最大连续 1 的个数是 3.
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示例 2:

输入：nums = [1,0,1,1,0,1]
输出：2
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Example 1:

Input: nums = [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
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Example 2:

Input: nums = [1,0,1,1,0,1]
Output: 2
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提示：

1 <= nums.length <= 105
nums[i] 不是 0 就是 1.

/**
 * @param {number[]} nums
 * @return {number}
 */
var findMaxConsecutiveOnes = function (nums) {
    let n = 0
    let max = 0
    for (let i = 0; i < nums.length; i++) {
        if (nums[i] == 1) {
            n++
        } else {
            //当遇到0，连续中断需要重置为0
            n = 0
        }
        //每次循环都进行取最大值
        max = Math.max(max, n)
    }
    return max
};
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leetcode:https://leetcode.cn/problems/max-consecutive-ones/