算法设计与分析双击调度自写

#include
 
using namespace std;
 
int main()
 
{
	int a[6];
	int b,c,sum = 0;
	int sub;
	int mm;
	int x1,y1,z1;
	int min = 100000;
	for(int i = 0; i < 6; i++) {
		cin >> a[i];
		sum += a[i];
	}
	//如果我们需要找到最小时间，就要要求两个机器完成时间差最小 
	for(int i = 0; i < 6; i++){
		for(int j = 0; j < 6; j++){
			for(int k = 0; k < 6; k++){
				
				if(i == j || j == k || i == k)continue;
				
				mm = a[i] + a[j] + a[k];
				sub = sum - mm;
				
				if(sub >= mm){
					int xx = sub - mm;
					if(xx < min) {
						x1 = i,y1 = j,z1 = k;
						min = xx;
					}
				}
				else{
					int xx = mm - sub;
					if(xx < min) {
						x1 = i,y1 = j,z1 = k;
						min = xx;
					}
				}
			}
		}
	}
	cout << x1 << " " << y1 << " " << z1 << endl;
	int ss = a[x1] + a[y1] + a[z1];
	cout << ss << " " << sum;
	return 0;
	
}