和最长公共子序列相似,不同之处在于这一道题只有母序列(较长的序列)可以进行删除操作,体现在遍历中就是除了左上方之外,上方和下方只有一个可以转移过来。
- class Solution {
- public:
- bool isSubsequence(string s, string t) {
- vector
int>> dp(s.size() + 1, vector<int>(t.size() + 1, 0)); - for (int i = 1; i <= s.size(); i++) {
- for (int j = 1; j <= t.size(); j++) {
- if (s[i - 1] == t[j - 1]) dp[i][j] = dp[i - 1][j - 1] + 1;
- else dp[i][j] = dp[i][j - 1];
- }
- }
- if (dp[s.size()][t.size()] == s.size()) return true;
- return false;
- }
- };
- class Solution {
- public:
- int numDistinct(string s, string t) {
- vector
uint64_t>> dp(s.size() + 1, vector<uint64_t>(t.size() + 1)); - for (int i = 0; i < s.size(); i++) dp[i][0] = 1;
- for (int j = 1; j < t.size(); j++) dp[0][j] = 0;
- for (int i = 1; i <= s.size(); i++) {
- for (int j = 1; j <= t.size(); j++) {
- if (s[i - 1] == t[j - 1]) {
- dp[i][j] = dp[i - 1][j - 1] + dp[i - 1][j];
- } else {
- dp[i][j] = dp[i - 1][j];
- }
- }
- }
- return dp[s.size()][t.size()];
- }
- };