You are given an integer array height
of length n
. There are n
vertical lines drawn such that the two endpoints of the ith
line are (i, 0)
and (i, height[i])
.
Find two lines that together with the x-axis form a container, such that the container contains the most water.
Return the maximum amount of water a container can store.
Notice that you may not slant the container.
Example 1:
Input: height = [1,8,6,2,5,4,8,3,7] Output: 49 Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example 2:
Input: height = [1,1] Output: 1
- class Solution {
- public int maxArea(int[] height) {
- if(height == null || height.length == 0){
- return 0;
- }
- int i=0, j=height.length-1; //两个指针往中间移动,每次选长的那个条
- int max = 0;
- while(i<=j){
- max = Math.max(max, Math.min(height[i],height[j]) * (j-i));
- if(height[i]<=height[j]){
- i++;
- }else{
- j--;
- }
- }
- return max;
- }
- }