• MYSQL练习题


    1、创建表

    1. 1、student表
    2. create table Student(SId varchar(10),Sname varchar(10),Sage datetime,Ssex varchar(10));
    3. insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
    4. insert into Student values('02' , '钱电' , '1990-12-21' , '男');
    5. insert into Student values('03' , '孙风' , '1990-12-20' , '男');
    6. insert into Student values('04' , '李云' , '1990-12-06' , '男');
    7. insert into Student values('05' , '周梅' , '1991-12-01' , '女');
    8. insert into Student values('06' , '吴兰' , '1992-01-01' , '女');
    9. insert into Student values('07' , '郑竹' , '1989-01-01' , '女');
    10. insert into Student values('09' , '张三' , '2017-12-20' , '女');
    11. insert into Student values('10' , '李四' , '2017-12-25' , '女');
    12. insert into Student values('11' , '李四' , '2012-06-06' , '女');
    13. insert into Student values('12' , '赵六' , '2013-06-13' , '女');
    14. insert into Student values('13' , '孙七' , '2014-06-01' , '女');
    15. 2、course表
    16. create table Course(CId varchar(10),Cname nvarchar(10),TId varchar(10));
    17. insert into Course values('01' , '语文' , '02');
    18. insert into Course values('02' , '数学' , '01');
    19. insert into Course values('03' , '英语' , '03');
    20. 3、teacher表
    21. create table Teacher(TId varchar(10),Tname varchar(10));
    22. insert into Teacher values('01' , '张三');
    23. insert into Teacher values('02' , '李四');
    24. insert into Teacher values('03' , '王五');
    25. 4、成绩表SC
    26. create table SC(SId varchar(10),CId varchar(10),score decimal(18,1));
    27. insert into SC values('01' , '01' , 80);
    28. insert into SC values('01' , '02' , 90);
    29. insert into SC values('01' , '03' , 99);
    30. insert into SC values('02' , '01' , 70);
    31. insert into SC values('02' , '02' , 60);
    32. insert into SC values('02' , '03' , 80);
    33. insert into SC values('03' , '01' , 80);
    34. insert into SC values('03' , '02' , 80);
    35. insert into SC values('03' , '03' , 80);
    36. insert into SC values('04' , '01' , 50);
    37. insert into SC values('04' , '02' , 30);
    38. insert into SC values('04' , '03' , 20);
    39. insert into SC values('05' , '01' , 76);
    40. insert into SC values('05' , '02' , 87);
    41. insert into SC values('06' , '01' , 31);
    42. insert into SC values('06' , '03' , 34);
    43. insert into SC values('07' , '02' , 89);
    44. insert into SC values('07' , '03' , 98);

    2、练习

    1. 1、查询" 01 "课程比" 02 "课程成绩高的学生的信息及课程分数
    2. select * from student left join (select t01.SId, score1, score2 from (select SId,score as score1 from sc where sc.CId='01') as t01, (select SId,score as score2 from sc where sc.CId='02') as t02 where t01.SId=t02.SId and t01.score1>t02.score2) as r on(student.SId=r.SId);
    3. 1.1、查询同时存在" 01 "课程和" 02 "课程的情况
    4. select * from (select * from sc where sc.CId='01') as s1, (select * from sc where sc.CId='02') as s2 where s1.SId=s2.SId;
    5. 1.2、查询存在" 01 "课程但可能不存在" 02 "课程的情况(不存在时显示为 null )
    6. select * from (select * from sc where sc.CId='01') as s1 left join (select * from sc where sc.CId='02') as s2 on(s1.SId=s2.SId);
    7. 1.3、查询不存在" 01 "课程但存在" 02 "课程的情况
    8. select * from sc where sc.SId not in (select SId from sc where sc.CId='01') and sc.CId='02';
    9. select * from sc where SId not in (select SId from sc where CId='01') and CId='02';
    10. 2、查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩
    11. select SId,Sname,avg(score) from (select * from student as stu inner join sc on(stu.SId=sc.SId)) where avg(score)>60 group by SId;
    12. 3、查询在sc表存在成绩的学生的信息
    13. select * from student right join (select SId,score from sc) on (student.SId=sc.SId);
    14. 4、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null )
    15. select * from (select SId,Sname from student)r right join (select SId,count(CId),sum(score) from sc group by SId)a on (r.SId=a.SId);
    16. 4.2、查询有成绩的学生的信息
    17. select * from student right join
    18. (select SId,score from sc )r on (student.SId=r.SId);
    19. 5、查询李姓老师的数量
    20. select count(Tname) from Teacher where Tname like '李%';
    21. 6、查询学过「张三」老师授课的同学的信息
    22. select * from student (select CId from sc where CId='02';
    23. 7、查询没有学全所有课程的同学的信息
    24. select * from student where student.sid not in (select sc.sid from sc group by sc.sid having count(sc.cid)= (select count(cid) from course));
    25. 8、查询至少有一门课与学号为" 01 "的同学所学相同的同学的信息
    26. select * from student where student.sid in (select sc.sid from sc where sc.cid in (select sc.cid from sc where sc.sid='01'));
    27. 10、查询没学过"张三"老师讲授的任一门课程的学生姓名
    28. select sname from student where student.sid not in (select sid from sc where cid='02' group by sid);
    29. 11、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
    30. select student.sid,student.sname,b.avg from student right join (select sid,avg(score) as avg from sc where sc.sid in (select sid from sc where sc.score<60 group by sid having count(score)>1 ) group by sid )b on student.sid=b.sid;
    31. 12、检索" 01 "课程分数小于 60,按分数降序排列的学生信息
    32. select student.*,score from student right join (select sid,score from sc where cid='01' and score<60 order by score desc)r on student.sid=r.sid;
    33. 13、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
    34. select student.sid,sum(r.score),avg(r.score) from ( select course.cname,sc.sid,sc.score from course,sc where course.cid=sc.cid)r,student where student.sid=r.sid group by sid order by avg(r.score);
    35. 14、查询各科成绩最高分、最低分和平均分
    36. select course.cname,r.* from course right join (select cid,max(score),min(score),avg(score) from sc group by cid)r on course.cid=r.cid;
    37. 15、按各科成绩进行排序,并显示排名, Score 重复时保留名次空缺
    38. select a.cid, a.sid, a.score, count(b.score)+1 as rank from sc as a left join sc as b on a.score
    39. 16、查询学生的总成绩,并进行排名,总分重复时不保留名次空缺
    40. set @crank=0;
    41. select q.sid, total, @crank := @crank +1 as rank from(select sc.sid, sum(sc.score) as total from sc group by sc.sid order by total desc)q;
    42. 17、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0] 及所占百分比
    43. select course.cname, course.cid,
    44. sum(case when sc.score<=100 and sc.score>85 then 1 else 0 end) as "[100-85]",
    45. sum(case when sc.score<=85 and sc.score>70 then 1 else 0 end) as "[85-70]",
    46. sum(case when sc.score<=70 and sc.score>60 then 1 else 0 end) as "[70-60]",
    47. sum(case when sc.score<=60 and sc.score>0 then 1 else 0 end) as "[60-0]"
    48. from sc left join course
    49. on sc.cid = course.cid
    50. group by sc.cid;
    51. 18、查询各科成绩前三名的记录
    52. select * from sc where (select count(*) from sc as a where sc.cid = a.cid and sc.score
    53. 19、查询每门课程被选修的学生数
    54. select cid,count(sid) from sc group by cid;
    55. 20、查询出只选修两门课程的学生学号和姓名
    56. select student.sid,student.sname from stuednt right join ( select sid,count(cid) from sc group by sid having count(cid)=2)r on student.sid=r.sid;
    57. 21、查询男生,女生的人数
    58. select Ssex,count(Ssex) from student group by Ssex;
    59. 22、查询名字中含有「风」字的学生信息
    60. select * from student where sname like '%风%';
    61. 23、查询同名同性学生名单,并统计同名人数
    62. select sname,count(*) from student group by sname having count(*)>1;
    63. 24、查询 1990 年出生的学生名单
    64. select sname from student where year(sage)=1990;
    65. 25、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列
    66. select cid,avg(score) from sc as a group by cid order by a desc,cid asc;
    67. 26、查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩
    68. select student.sid,student.sname,r.avg from student right join (select sid,avg(score) as avg from sc group by sid having avg(score)>85)r on student.sid=r.sid;
    69. 27、查询课程名称为「数学」,且分数低于 60 的学生姓名和分数
    70. select student.sname,sc.score from student,sc where student.sid=sc.sid and
    71. sc.cid='02' and sc.score<60;
    72. 28、查询所有学生的课程及分数情况(存在学生没成绩,没选课的情况)
    73. select student.sname,sc.cid,sc.score from student left join sc on student.sid=sc.sid;
    74. 29、查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数
    75. select student.sname,r.cname,r.score from student right join (select course.cname,sc.score,sc.sid from course,sc where course.cid=sc.cid and sc.score>70)r on student.sid=r.sid;
    76. 30、查询不及格的课程
    77. select course.cname,sc.score from course right join sc on course.cid=sc.cid where sc.score<60;
    78. 31、查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名
    79. select sc.sid,student.sname from student,sc where student.sid=sc.sid and sc.cid='01' and sc.score>80;
    80. 32、求每门课程的学生人数
    81. select cid,count(sid) from sc group by cid;
    82. 33、成绩不重复,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩
    83. select student.*,r.max(score) from student right join (select cid,max(score) from sc group by cid having sc.cid='02')r on student.sid;
    84. 34、成绩有重复的情况下,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩
    85. update sc set score=90 where sid = "07" and cid ="02";
    86. 35、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
    87. select a.* from sc as a right join sc as b on a.sid=b.sid where a.cid!=b.cid and a.score=b.score group by sid,cid,score;
    88. 36、查询每门功成绩最好的前两名
    89. select a.sid,a.cid,a.score from sc as a left join sc as b on a.cid = b.cid and a.score
    90. 37、统计每门课程的学生选修人数(超过 5 人的课程才统计)。
    91. select cid,count(sid) from sc group by cid having count(sid)>5;
    92. 38、检索至少选修两门课程的学生学号
    93. select sid,coount(cid) from sc group by sid having count(sid)>=2;
    94. 39、查询选修了全部课程的学生信息
    95. select student.* from student right join (select sid,coount(cid) from sc group by sid having count(sid)=3)r on student.sid=r.sid;
    96. 41、按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一
    97. select * from student as stu where weekofyear(stu.Sage)=weekofyear(curdate());
    98. 42、查询本周过生日的学生
    99. select * from student as stu where weekofyear(stu.Sage)=weekofyear(curdate());
    100. 43、查询下周过生日的学生
    101. select * from student as stu where weekofyear(stu.Sage)=weekofyear(curdate())+1;
    102. 44、查询本月过生日的学生
    103. select * from student as stu where month(stu.Sage)=month(curdate());
    104. 45、查询下月过生日的学生
    105. select * from student as stu where month(stu.Sage)=month(curdate())+1;

    注:下面题与上无关

    面试题

    1. 1.向student表中插入一条数据
    2. insert into Student values(2,'张三''男','水浒传');
    3. 2.查询课程名为数据库,且分数低于60的学生姓名与分数
    4. select S.name,SC.degree from Student as S right join Score as SC on S.sco=SC.sco where SC.cno='数据库' and SC.degree<60;
    5. 3.对于所有性别为女的学生,同时课程名为高等数学的分数统一加5
    6. update Score SC set degree=degree+5 where SC.sno in (select sno from Student S where Ssex='女') and SCCcno in (select C.Cno from Course C where C.Cname='高等数学');
    7. 4.删除姓名为‘张翰’(学号=1)课程名为数据库的课程成绩
    8. delete from Score where Sno=1 and Cno in (select c.Cno from Course c where c.Cname='数据库');

    作业题

    1. 第六章作业:
    2. create table course(
    3. cno int primary key,
    4. cname varchar(20)
    5. );
    6. create table sc(
    7. sno int,
    8. cno int,
    9. score int,
    10. primary key(sno,cno)
    11. );
    12. 1.用SQL语句创建学生表student,定义主键,姓名不能重名,性别只能输入男或女,所在系的默认值是 “计算机”。
    13. create table student(
    14. sno int primary key,
    15. sname varchar(20) unique,
    16. ssex enum('男','女'),
    17. age int,
    18. 所在系 varchar(20) default "计算机"
    19. );
    20. 2.修改student 表中年龄(age)字段属性,数据类型由int 改变为smallint
    21. alter table student modifiy age smallint
    22. 3.为SC表建立按学号(sno)和课程号(cno)组合的升序的主键索引,索引名为SC_INDEX
    23. create index sc_index on sc (sno,cno asc);
    24. 4.创建一视图 stu_info,查询全体学生的姓名,性别,课程名,成绩
    25. select student.sname,student.ssex r.cno,r.score from student right join
    26. (select sno,cno,score from course,sc where course.cno=sc.cno)r on student.sno=r.sno;
    27. 创建表并插入数据
    28. create table student1(
    29. id int primary key not null unique,
    30. name varchar(20) not null,
    31. glass varchar(20) not null
    32. );
    33. create table sch (
    34. id int primary key,
    35. name varchar(20) unique,
    36. glass varchar(20)
    37. );
    38. 第七章作业:
    39. 1、创建一个可以统计表格内记录条数的存储函数 ,函数名为count_sch()
    40. create function p1()
    41. returns int
    42. begin
    43. declare i int default 0;
    44. select count(*) into i from sch;
    45. return i;
    46. end$
    47. select p1();
    48. 2.创建一个存储过程avg_sai,有3个参数,分别是deptno,job,接收平均工资,功能查询emp表dept为30,job为销售员的平均工资。
    49. create procedure avg_sai (in deprtno int,in job varchar(20),out a int)
    50. begin
    51. select avg(salary) into a from emp where dept=30 and work='销售员';
    52. end$
    53. call avg_sai(dept,job,@a);

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  • 原文地址:https://blog.csdn.net/qq_64951792/article/details/134067066