【Mysql】关联查询1对多处理

关联查询1对多返回

遇见的问题

审批主表，和审批明细表，一张审批对应多张明细数据，每条明细数据的状态是不一样的，现在需要根据明细的状态获取到主单子的状态，状态返回矩阵如下

观察报错

无

问题解决

SELECT vba.object_id,
       vba.create_time,
       vba.company_id,
       vba.approval_no,
       vba.finish_time,
       vba.business_table,
       vba.business_id,
       t2.enum_status,
       vba.create_user_name,
       vba.apply_abstract
FROM view_bus_approval vba
         LEFT JOIN view_bus_payment vbp ON vba.object_id = vbp.approval_id
         LEFT JOIN (SELECT ba.approval_id,
                           CASE
                               WHEN ba.enum_status = '05'
                                   AND ba.cnt > 0 THEN
                                   '05'
                               WHEN ba.enum_status = '10'
                                   AND ba.cnt > 0 THEN
                                   '10'
                               WHEN ba.enum_status = '20'
                                   AND ba.cnt = ba1.cnt THEN
                                   '20'
                               WHEN ba.enum_status = '30'
                                   AND ba.cnt = ba1.cnt THEN
                                   '30'
                               WHEN ba.enum_status = '40'
                                   AND ba.cnt = ba1.cnt THEN
                                   '40'
                               ELSE '20'
                               END AS enum_status
                    FROM (SELECT t2.approval_id,
                                 t2.enum_status,
                                 sum(cnt) AS cnt
                          FROM view_approval_detail_status_cnt t2
                          WHERE t2.approval_user_id = 1
                          GROUP BY t2.approval_id,
                                   t2.enum_status) ba
                             LEFT JOIN (SELECT t2.approval_id, sum(cnt) AS cnt
                                        FROM view_approval_detail_status_cnt t2
                                        WHERE t2.approval_user_id = 1
                                        GROUP BY t2.approval_id) ba1 ON ba1.approval_id = ba.approval_id
                    GROUP BY ba.approval_id) t2 ON t2.approval_id = vba.object_id
WHERE vba.is_deleted = 0
  AND vba.business_table = 'bus_official_seal_use'
ORDER BY (
             CASE
                 vba.enum_status
                 WHEN '05' THEN
                     1
                 WHEN '30' THEN
                     2
                 WHEN '10' THEN
                     3
                 WHEN '40' THEN
                     4
                 WHEN '20' THEN
                     5
                 ELSE 6
                 END
             ) ASC,
         vba.create_time DESC;
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62

这里用到了两层查询，一遍是查询该申请单子的所有明细的数量

SELECT t2.approval_id, sum(cnt) AS cnt
FROM view_approval_detail_status_cnt t2
WHERE t2.approval_user_id = 1
GROUP BY t2.approval_id
1
2
3
4

然后外层是查询该单子下再按照状态进行分组求和

SELECT t2.approval_id,
       t2.enum_status,
       sum(cnt) AS cnt
FROM view_approval_detail_status_cnt t2
WHERE t2.approval_user_id = 1
GROUP BY t2.approval_id,
         t2.enum_status
1
2
3
4
5
6
7

然后拿到的申请单id，再group by这个单子id，因为一个单子只会返回一个状态，就达到效果了。

结语

如果哪位大佬发现了解释的不对的，还望不吝赐教。十分感谢