P8218 【深进1.例1】求区间和

#include 
using namespace std;
int a[100010],s[100010];
int main()
{
    int n;
    cin >> n;
    for(int i = 1;i <= n;i++)
    {
        cin >> a[i];
        s[i] = s[i - 1] + a[i];
    }
    int q;
    cin >> q;
    for(int i = 1;i <= q;i++)
    {
        int l,r;
        cin >> l >> r;
        cout << s[r] - s[l - 1] << endl;
    }
    return 0;
}