语法练习：monkey_trouble

语法练习：monkey_trouble

题目：monkey_trouble

We have two monkeys, a and b, and the parameters a_smile and b_smile indicate if each is smiling. We are in trouble if they are both smiling or if neither of them is smiling. Return True if we are in trouble.

monkey_trouble(True, True) → True
monkey_trouble(False, False) → True
monkey_trouble(True, False) → False

我的解答：

def monkey_trouble(a_smile, b_smile):
  return a_smile==b_smile
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Expected Run
monkey_trouble(True, True) → True True OK
monkey_trouble(False, False) → True True OK
monkey_trouble(True, False) → False False OK
monkey_trouble(False, True) → False False OK

All Correct

标答：

def monkey_trouble(a_smile, b_smile):
  if a_smile and b_smile:
    return True
  if not a_smile and not b_smile:
    return True
  return False
  ## The above can be shortened to:
  ##   return ((a_smile and b_smile) or (not a_smile and not b_smile))
  ## Or this very short version (think about how this is the same as the above)
  ##   return (a_smile == b_smile)
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