python实现对象列表根据某个属性排序的方法详解

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#coding:utf-8

class Person:

  def __init__(self,name,age,salary):

    self.name = name

    self.age = age

    self.salary = salary

obj_list = [

      Person('juneys',20,30000),

      Person('sam',20,20000),

      Person('eddy',22,25000),

      Person('eagle',25,10000)

      ]

#第一种方法

obj_list.sort(cmp=None, key=lambda x:x.salary, reverse=False)

print '***********第一种方法***********************'

for obj in obj_list:

  print obj.name,obj.salary

# 第二种方法,更适合于大量数据的情况.

try:

  import operator

except ImportError:

  cmpfun= lambda x: x.count # use a lambda if no operator module

else:

  cmpfun= operator.attrgetter("salary") # use operator since it's faster than lambda

obj_list.sort(key=cmpfun, reverse=True)

print '***********第二种方法***********************'

for obj in obj_list:

  print obj.name,obj.salary