几个算法题解

import math
import time
import random
import string
from scipy.stats import t

#喊七，按照题目要求，实质就是对输入数据进行排序即可，由大到小、
#喊七，逢七过，未知人数，未知什么时候结尾，在只知道每个人喊了多少次过的情况下，需要根据每个人喊过的次数来重新排列出他们分别是在几号位，即第几个开始喊的

def seven_counts(player_num,ed_num):
    temp_list = ['过' if i % 7 == 0 or '7' in str(i) else i for i in range(1,ed_num)]
    temp_dict = {}
    all_value = []
    for i in range(math.ceil(len(temp_list)/player_num)):
        all_value.append(temp_list[player_num*i:(i+1)*player_num])
    for i in range(len(all_value)):
        for j in range(len(all_value[i])):
            if all_value[i][j] == '过' and j not in temp_dict.keys():
                temp_dict[j] = 1
            elif all_value[i][j] == '过':
                temp_dict[j] += 1
            else:
                pass
    return temp_dict

def seven_function():
    input_value = input('please input the num:\t')
    origin_list = input_value.split(' ')
    player_num = len(origin_list)
    counts = sum([int(i) for i in origin_list])
    s = 1
    while True:
        result = seven_counts(player_num,s)
        s += 1
        if sum(list(result.values())) == counts:
            for i in range(len(result.keys())):
                print(result[i],end=' ')
            break

#最长子字符串长度,首尾相连成环形、
#统计以o结尾且为偶数位的长度，如果字符串中含o的个数为奇数，则取到前一个即可
def length_str(strs):
    temp_list = []
    for i in range(len(strs)):
        if strs[i] == 'o':
            temp_list.append(i)
    if len(temp_list) % 2 == 0:
        print(temp_list[len(temp_list)-1] + 1)
    #     print(max(len(temp_list)))
    else:
        print(temp_list[len(temp_list) - 2] + 1)
# 字符串统计及排序
#统计一个字符串中每个字母出现的次数并排序，按照字母自然顺序排列
def sort_str(strs):
    temp_dict = {}
    for word in strs:
        if word not in temp_dict.keys():
            temp_dict[word] = 1
        else:
            temp_dict[word] += 1
    for keys_word in string.ascii_letters:
        for j in temp_dict.keys():
            if j == keys_word:
                print('%s:%s'%(j,temp_dict[j]),end=';')

#字符串反转
#将每个字符串做为一个基本元素对象进行翻转
def reverse_words(strs):
    args_word = strs.split('\n')
    st_num = int(args_word[1])
    ed_num = int(args_word[2])
    words = args_word[0].split(' ')
    words[st_num:ed_num+1] = words[st_num:ed_num+1][::-1]
    print(' '.join(words))

说明：如果有人看了这个文档之后，题目建议自己去找一下，我这边只是为了方便自己看一下逻辑，所以题目没有写的很清楚，只写了一些关键字。