• 快速傅里叶变换(FFT)


    文章目录


    暂时只能理解这是干嘛的,以及该怎么用。。。

    卷积
    给定向量: a = ( a 0 , a 1 , . . . , a n − 1 ) a=(a_0,a_1,...,a_{n−1}) a=(a0,a1,...,an1) b = ( b 0 , b 1 , . . . , b n − 1 ) b=(b_0,b_1,...,b_{n−1}) b=(b0,b1,...,bn1)
    向量和: a + b = ( a 0 + b 0 , a 1 + b 1 , . . . , a n − 1 + b n − 1 ) a+b=(a_0+b_0,a_1+b_1,...,a_{n−1}+b_{n−1}) a+b=(a0+b0,a1+b1,...,an1+bn1)
    数量积(内积、点积): a ⋅ b = a 0 b 0 + a 1 b 1 + . . . + a n − 1 b n − 1 a⋅b=a_0b_0+a_1b_1+...+a_{n−1}b_{n−1} ab=a0b0+a1b1+...+an1bn1
    卷积: a ⊗ b = ( c 0 , c 1 , . . . , c 2 n − 2 ) a⊗b=(c_0,c_1,...,c_{2n−2}) ab=(c0,c1,...,c2n2),其中 c k = ∑ i + j = k ( a i b j ) c_k=∑_{i+j=k}(a_ib_j) ck=i+j=k(aibj)
    卷积的最典型的应用就是多项式乘法(多项式乘法就是求卷积)。

    a ⊗ b = I D F T 2 n ( D F T 2 n ( a ) ⋅ D F T 2 n ( b ) ) a⊗b=IDFT_{2n}(DFT_{2n}(a)⋅DFT_{2n}(b)) ab=IDFT2n(DFT2n(a)DFT2n(b)),即: a ⊗ b = D F T 2 n − 1 ( D F T 2 n ( a ) ⋅ D F T 2 n ( b ) ) a⊗b=DFT^{−1}_{2n}(DFT_{2n}(a)⋅DFT_{2n}(b)) ab=DFT2n1(DFT2n(a)DFT2n(b))

    #include 
    
    #define fp(i, a, b) for (int i = (a), i##_ = (b) + 1; i < i##_; ++i)
    using namespace std;
    using ll = int64_t;
    using db = double;
    /*---------------------------------------------------------------------------*/
    struct cp
    {
        db x, y;
        cp(db real = 0, db imag = 0) : x(real), y(imag){};
        cp operator+(cp b) const
        {
            return {x + b.x, y + b.y};
        }
        cp operator-(cp b) const
        {
            return {x - b.x, y - b.y};
        }
        cp operator*(cp b) const
        {
            return {x * b.x - y * b.y, x * b.y + y * b.x};
        }
    };
    using vcp = vector;
    using Poly = vector;
    namespace FFT
    {
    const db pi = acos(-1);
    vcp Omega(int L)
    {
        vcp w(L);
        w[1] = 1;
        for (int i = 2; i < L; i <<= 1)
        {
            auto w0 = w.begin() + i / 2, w1 = w.begin() + i;
            cp wn(cos(pi / i), sin(pi / i));
            for (int j = 0; j < i; j += 2)
                w1[j] = w0[j >> 1], w1[j + 1] = w1[j] * wn;
        }
        return w;
    }
    auto W = Omega(1 << 21); // NOLINT
    void DIF(cp *a, int n)
    {
        cp x, y;
        for (int k = n >> 1; k; k >>= 1)
            for (int i = 0; i < n; i += k << 1)
                for (int j = 0; j < k; ++j)
                    x = a[i + j], y = a[i + j + k], a[i + j + k] = (a[i + j] - y) * W[k + j], a[i + j] = x + y;
    }
    void IDIT(cp *a, int n)
    {
        cp x, y;
        for (int k = 1; k < n; k <<= 1)
            for (int i = 0; i < n; i += k << 1)
                for (int j = 0; j < k; ++j)
                    x = a[i + j], y = a[i + j + k] * W[k + j], a[i + j + k] = x - y, a[i + j] = x + y;
        const db Inv = 1. / n;
        fp(i, 0, n - 1) a[i].x *= Inv, a[i].y *= Inv;
        reverse(a + 1, a + n);
    }
    } // namespace FFT
    
    namespace Polynomial
    {
    // basic operator
    void DFT(vcp &a)
    {
        FFT::DIF(a.data(), a.size());
    }
    void IDFT(vcp &a)
    {
        FFT::IDIT(a.data(), a.size());
    }
    int norm(int n)
    {
        return 1 << (__lg(n - 1) + 1);
    }
    
    // Poly mul
    vcp &dot(vcp &a, vcp &b)
    {
        fp(i, 0, a.size() - 1) a[i] = a[i] * b[i];
        return a;
    }
    Poly operator+(Poly a, Poly b)
    {
        int maxlen = max(a.size(), b.size());
        Poly ans(maxlen + 1);
        a.resize(maxlen + 1), b.resize(maxlen + 1);
        for (int i = 0; i < maxlen; i++)
            ans[i] = a[i] + b[i];
        return ans;
    }
    Poly operator*(ll k, Poly a)
    {
        Poly ans;
        for (auto i : a)
            ans.push_back(k * i);
        return ans;
    }
    Poly operator*(Poly a, Poly b)
    {
        int n = a.size() + b.size() - 1;
        vcp c(norm(n));
        fp(i, 0, a.size() - 1) c[i].x = a[i];
        fp(i, 0, b.size() - 1) c[i].y = b[i];
        DFT(c), dot(c, c), IDFT(c), a.resize(n);
        fp(i, 0, n - 1) a[i] = int(c[i].y * .5 + .5);
        return a;
    }
    } // namespace Polynomial
    /*---------------------------------------------------------------------------*/
    using namespace Polynomial;
    const int N = 5e4 + 10;
    int main()
    {
        ios::sync_with_stdio(0), cin.tie(0);
        int n, m;
        cin >> n >> m;
        Poly a(n + 1), b(m + 1), c(n + m + 1);
        for (int i = 0; i <= n; i++)
            cin >> a[i];
        for (int i = 0; i <= m; i++)
            cin >> b[i];
        c = a * b;
        for (int i = 0; i <= n + m; i++)
            cout << c[i] << " ";
        return 0;
    }
    
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  • 原文地址:https://blog.csdn.net/qq_61540355/article/details/126810714