+-------+---------+--------+
| ename | sal | deptno |
+-------+---------+--------+
| BLAKE | 2850.00 | 30 |
| SCOTT | 3000.00 | 20 |
| KING | 5000.00 | 10 |
| FORD | 3000.00 | 20 |
+-------+---------+--------+
思路:获取每个部门的最高薪资和部门编号,作为临时表t;再与emp表联合查询。
select
e.ename,t.*
from
emp e
join
(select max(sal) as sal,deptno from emp group by deptno) t
on
e.deptno=t.deptno and e.sal=t.sal;
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2.哪些人的薪水在部门的平均薪水之上
+-------+---------+--------+
| ename | sal | deptno |
+-------+---------+--------+
| ALLEN | 1600.00 | 30 |
| JONES | 2975.00 | 20 |
| BLAKE | 2850.00 | 30 |
| SCOTT | 3000.00 | 20 |
| KING | 5000.00 | 10 |
| FORD | 3000.00 | 20 |
+-------+---------+--------+
思路:获取每个部门的平均薪水,部门编号作为临时表t;再与emp表联合查询。
select
e.ename,e.sal,e.deptno
from
emp e
join
(select deptno,avg(sal) as avgsal from emp group by deptno) t
on
e.deptno=t.deptno and e.sal>t.avgsal;
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3.取得部门中(所有人的)平均的薪水等级
+--------+--------------+
| deptno | avg(s.grade) |
+--------+--------------+
| 20 | 2.8000 |
| 30 | 2.5000 |
| 10 | 3.6667 |
+--------+--------------+
思路:先获取每个人的薪水等级,然后分组进行avg求每个部门的平均薪水等级
select
e.deptno,avg(s.grade)
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal
group by
e.deptno;
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4.取得最高薪水(给出三种解决方案)
+---------+
| sal |
+---------+
| 5000.00 |
+---------+
第一种·:max()函数
select max(sal) from emp;
第二种:降序,limit
select
sal
from
emp
order by
sal desc
limit
1;
第三种:表的自连接
思路:子查询获得一张不包含最大值的表,然后进行not in操作
第一步:子查询获得一张不包含最大值的表t
select
distinct a.sal
from
emp a
join
emp b
on
a.sal
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5.取得平均薪水最高的部门的部门编号(至少给出两种解决方案)
+--------+-------------+
| deptno | avgsal |
+--------+-------------+
| 10 | 2916.666667 |
+--------+-------------+
第一种:降序第一个。
思路:先分组求出每组的薪资平均值,然后对表降序排序,limit 1 获得。
select
deptno,avg(sal) as avgsal
from
emp
group by
deptno
order by
avgsal desc
limit
1;
第二种:max()函数
思路:先找出每个部门的平均薪水,再该表找出avgsal最大的值,再与该表进行having筛选操作
//这里是找出每个部门的平均薪水
select deptno,avg(sal) as avgsal from emp group by deptno;
//这里是找出avgsal最大的值
select
max(t.avgsal)
from
(select deptno,avg(sal) as avgsal from emp group by deptno) t;
//having筛选
select
deptno,avg(sal) as avgsal
from
emp
group by
deptno
having
avgsal=(select max(t.avgsal) from (select deptno,avg(sal) as avgsal from emp group by deptno) t);
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6.取得平均薪水最高的部门的部门名称
+------------+-------------+
| dname | avgsal |
+------------+-------------+
| ACCOUNTING | 2916.666667 |
+------------+-------------+
select
d.dname,avg(e.sal) as avgsal
from
emp e
join
dept d
on
e.deptno=d.deptno
group by
d.dname
order by
avgsal desc
limit
1;
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7.求平均薪水的等级最低的部门的部门名称
+-------+-------------+-------+
| dname | avgsal | grade |
+-------+-------------+-------+
| SALES | 1566.666667 | 3 |
+-------+-------------+-------+
select
d.dname,avg(e.sal) as avgsal,s.grade
from
emp e
join
dept d
on
d.deptno=e.deptno
join
salgrade s
on
e.sal between s.losal and s.hisal
group by
d.dname
order by
avgsal asc
limit
1;
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8.取得比普通员工(员工代码没有在mgr字段上出现的)的最高薪水还要高的领导人姓名
+-------+---------+
| ename | sal |
+-------+---------+
| JONES | 2975.00 |
| BLAKE | 2850.00 |
| CLARK | 2450.00 |
| SCOTT | 3000.00 |
| KING | 5000.00 |
| FORD | 3000.00 |
+-------+---------+
第一步:找出领导人列表
select distinct mgr from emp where mgr is not null;
+------+
| mgr |
+------+
| 7902 |
| 7698 |
| 7839 |
| 7566 |
| 7788 |
| 7782 |
+------+
第二步:找出普通员工最高的薪资
select max(sal) from emp where empno not in(select distinct mgr from emp where mgr is not null);
+----------+
| max(sal) |
+----------+
| 1600.00 |
+----------+
第三步:从emp中找出高于1600的
select ename,sal from emp where sal>(select max(sal) from emp where empno not in(select distinct mgr from emp where mgr is not null));
+-------+---------+
| ename | sal |
+-------+---------+
| JONES | 2975.00 |
| BLAKE | 2850.00 |
| CLARK | 2450.00 |
| SCOTT | 3000.00 |
| KING | 5000.00 |
| FORD | 3000.00 |
+-------+---------+
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9.取得薪水最高的前五名员工
select
ename,sal
from
emp
order by
sal desc
limit
5;
+-------+---------+
| ename | sal |
+-------+---------+
| KING | 5000.00 |
| SCOTT | 3000.00 |
| FORD | 3000.00 |
| JONES | 2975.00 |
| BLAKE | 2850.00 |
+-------+---------+
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10.取得薪水最高的第六到第十名员工
select
ename,sal
from
emp
order by
sal desc
limit
5,5;
+--------+---------+
| ename | sal |
+--------+---------+
| CLARK | 2450.00 |
| ALLEN | 1600.00 |
| TURNER | 1500.00 |
| MILLER | 1300.00 |
| WARD | 1250.00 |
+--------+---------+
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11.取得最后入职的 5 名员工
select
ename,hiredate
from
emp
order by
hiredate desc
limit
5;
+--------+------------+
| ename | hiredate |
+--------+------------+
| ADAMS | 1987-05-23 |
| SCOTT | 1987-04-19 |
| MILLER | 1982-01-23 |
| JAMES | 1981-12-03 |
| FORD | 1981-12-03 |
+--------+------------+
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12.取得每个薪水等级有多少员工
思路:先找出每个员工的薪水等级,然后分组,求各组数量。
select
s.grade,count(*)
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal
group by
s.grade;
+-------+----------+
| grade | count(*) |
+-------+----------+
| 1 | 3 |
| 3 | 2 |
| 2 | 3 |
| 4 | 5 |
| 5 | 1 |
+-------+----------+
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13.列出所有员工及领导的姓名
select
e.ename,ifnull(l.ename,'没有上级')
from
emp e
left join
emp l
on
e.mgr=l.empno;
+--------+----------------------------+
| ename | ifnull(l.ename,'没有上级') |
+--------+----------------------------+
| SMITH | FORD |
| ALLEN | BLAKE |
| WARD | BLAKE |
| JONES | KING |
| MARTIN | BLAKE |
| BLAKE | KING |
| CLARK | KING |
| SCOTT | JONES |
| KING | 没有上级 |
| TURNER | BLAKE |
| ADAMS | SCOTT |
| JAMES | BLAKE |
| FORD | JONES |
| MILLER | CLARK |
+--------+----------------------------+
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14.列出受雇日期早于其直接上级的所有员工的编号,姓名,部门名称
select
distinct e.empno,e.ename,d.dname
from
emp e
join
dept d
on
e.deptno=d.deptno
join
emp l
on
e.mgr=l.empno
where
e.hiredate
select
d.dname,count(*)
from
dept d
join
emp e
on
d.deptno=e.deptno
group by
d.dname
having
count(*)>=5;
+----------+----------+
| dname | count(*) |
+----------+----------+
| RESEARCH | 5 |
| SALES | 6 |
+----------+----------+
第一步:找出所有'CLERK'的信息
select
e.ename,d.deptno,d.dname
from
emp e
join
dept d
on
e.deptno=d.deptno
where
e.job='CLERK';
+--------+--------+------------+
| ename | deptno | dname |
+--------+--------+------------+
| SMITH | 20 | RESEARCH |
| ADAMS | 20 | RESEARCH |
| JAMES | 30 | SALES |
| MILLER | 10 | ACCOUNTING |
+--------+--------+------------+ t1表
第二步:统计各部门的人数
select
d.deptno,count(*) as cc
from
emp e
join
dept d
on
e.deptno=d.deptno
group by
d.deptno;
+--------+----------+
| deptno | count(*) |
+--------+----------+
| 20 | 5 |
| 30 | 6 |
| 10 | 3 |
+--------+----------+ t2表
第三步:联合两个表
select
t1.ename,t1.dname,t2.cc
from
(select e.ename,d.deptno,d.dname from emp e join dept d on e.deptno=d.deptno where e.job='CLERK') t1
join
(select d.deptno,count(*) as cc from emp e join dept d on e.deptno=d.deptno group by d.deptno) t2
on
t1.deptno=t2.deptno;
+--------+------------+----+
| ename | dname | cc |
+--------+------------+----+
| SMITH | RESEARCH | 5 |
| ADAMS | RESEARCH | 5 |
| JAMES | SALES | 6 |
| MILLER | ACCOUNTING | 3 |
+--------+------------+----+
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19.列出最低薪金大于 1500 的各种工作及从事此工作的全部雇员人数
第一步:找出最低薪资大于1500的工作
select
job,min(sal) as minsal
from
emp
group by
job
having
minsal>1500;
+-----------+---------+
| job | minsal |
+-----------+---------+
| MANAGER | 2450.00 |
| ANALYST | 3000.00 |
| PRESIDENT | 5000.00 |
+-----------+---------+ t1表
第二步:找出每种工作的人数
select
job,count(*)
from
emp
group by
job;
+-----------+----------+
| job | count(*) |
+-----------+----------+
| CLERK | 4 |
| SALESMAN | 4 |
| MANAGER | 3 |
| ANALYST | 2 |
| PRESIDENT | 1 |
+-----------+----------+ t2表
第三步:联合两张表
select
t1.job,t2.count
from
(select
job,min(sal) as minsal
from
emp
group by
job
having
minsal>1500) t1
join
(select
job,count(*) as count
from
emp
group by
job) t2
on
t1.job=t2.job;
+-----------+-------+
| job | count |
+-----------+-------+
| MANAGER | 3 |
| ANALYST | 2 |
| PRESIDENT | 1 |
+-----------+-------+
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20.列出在部门"SALES"<销售部>工作的员工的姓名,假定不知道销售部的部门编号
第一种:表联合
select
e.ename
from
emp e
join
dept d
on
e.deptno=d.deptno
where
d.dname='SALES';
+--------+
| ename |
+--------+
| ALLEN |
| WARD |
| MARTIN |
| BLAKE |
| TURNER |
| JAMES |
+--------+
第二种:子查询
select
ename
from
emp
where
deptno=(select deptno from dept where dname='SALES');
+--------+
| ename |
+--------+
| ALLEN |
| WARD |
| MARTIN |
| BLAKE |
| TURNER |
| JAMES |
+--------+
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21.列出薪金高于公司平均薪金的所有员工,所在部门,上级领导,雇员的工资等级
select
e.ename,d.dname,ifnull(l.ename,'无'),s.grade
from
emp e
join
salgrade s
on
e.sal between s.losal and s.hisal
left join
emp l
on
e.mgr=l.empno
join
dept d
on
e.deptno=d.deptno
where
e.sal>(select avg(sal) as avgsal from emp);
+-------+------------+----------------------+-------+
| ename | dname | ifnull(l.ename,'无') | grade |
+-------+------------+----------------------+-------+
| FORD | RESEARCH | JONES | 4 |
| SCOTT | RESEARCH | JONES | 4 |
| CLARK | ACCOUNTING | KING | 4 |
| BLAKE | SALES | KING | 4 |
| JONES | RESEARCH | KING | 4 |
| KING | ACCOUNTING | 无 | 5 |
+-------+------------+----------------------+-------+
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22.列出与"SCOTT"从事相同工作的所有员工及部门名称
select
e.ename,d.dname
from
emp e
join
dept d
on
e.deptno=d.deptno
where
e.job=(select job from emp where ename='SCOTT') and e.ename!='SCOTT';
+-------+----------+
| ename | dname |
+-------+----------+
| FORD | RESEARCH |
+-------+----------+
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23.列出薪金等于部门 30 中员工的薪金的其他员工的姓名和薪金
第一步:查找部门30中员工的薪金
select distinct sal from emp where deptno=30;
+---------+
| sal |
+---------+
| 1600.00 |
| 1250.00 |
| 2850.00 |
| 1500.00 |
| 950.00 |
+---------+ t表
第二步:从emp表中查找薪资等于t表中薪资并且部门不为30的员工
select
ename,sal
from
emp
where
sal in(select distinct sal from emp where deptno=30) and deptno!=30;
Empty set (0.00 sec)
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24.列出薪金高于在部门 30 工作的所有员工的薪金的员工姓名和薪金,部门名称
第一步:找出部门30最高薪金
select max(sal) from emp where deptno=30;
+---------+
| max(sal) |
+---------+
| 2850.00 |
+---------+
第二步:从emp表中找薪金大于部门30最高薪金的员工
select
e.ename,e.sal,d.dname
from
emp e
join
dept d
on
e.deptno=d.deptno
where
sal>(select max(sal) from emp where deptno=30);
+-------+---------+------------+
| ename | sal | dname |
+-------+---------+------------+
| JONES | 2975.00 | RESEARCH |
| SCOTT | 3000.00 | RESEARCH |
| KING | 5000.00 | ACCOUNTING |
| FORD | 3000.00 | RESEARCH |
+-------+---------+------------+
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25.列出在每个部门工作的员工数量,平均工资和平均服务期限
计算两个日期之间的差值:
用法:timestampdiff(间隔类型, 前一个日期, 后一个日期)
间隔类型:
SECOND 秒,
MINUTE 分钟,
HOUR 小时,
DAY 天,
WEEK 星期
MONTH 月,
QUARTER 季度,
YEAR 年
//没有员工的部门,部门人数是0
select
d.deptno,count(e.ename) as ecount,avg(ifnull(e.sal,0)) as avgsal,avg(ifnull((timestampdiff(YEAR,e.hiredate,now())),0)) as avgservicetime
from
emp e
right join
dept d
on
e.deptno=d.deptno
group by
d.deptno;
+--------+--------+-------------+----------------+
| deptno | ecount | avgsal | avgservicetime |
+--------+--------+-------------+----------------+
| 10 | 3 | 2916.666667 | 40.3333 |
| 20 | 5 | 2175.000000 | 38.4000 |
| 30 | 6 | 1566.666667 | 40.5000 |
| 40 | 0 | 0.000000 | 0.0000 |
+--------+--------+-------------+----------------+
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26.列出所有员工的姓名、部门名称和工资
select
e.ename,d.dname,e.sal
from
emp e
join
dept d
on
e.deptno=d.deptno;
+--------+------------+---------+
| ename | dname | sal |
+--------+------------+---------+
| SMITH | RESEARCH | 800.00 |
| ALLEN | SALES | 1600.00 |
| WARD | SALES | 1250.00 |
| JONES | RESEARCH | 2975.00 |
| MARTIN | SALES | 1250.00 |
| BLAKE | SALES | 2850.00 |
| CLARK | ACCOUNTING | 2450.00 |
| SCOTT | RESEARCH | 3000.00 |
| KING | ACCOUNTING | 5000.00 |
| TURNER | SALES | 1500.00 |
| ADAMS | RESEARCH | 1100.00 |
| JAMES | SALES | 950.00 |
| FORD | RESEARCH | 3000.00 |
| MILLER | ACCOUNTING | 1300.00 |
+--------+------------+---------+
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27.列出所有部门的详细信息和人数
select
d.*,ifnull(count(e.ename),0) as '人数'
from
dept d
left join
emp e
on
d.deptno=e.deptno
group by
d.deptno;
+--------+------------+----------+------+
| DEPTNO | DNAME | LOC | 人数 |
+--------+------------+----------+------+
| 10 | ACCOUNTING | NEW YORK | 3 |
| 20 | RESEARCH | DALLAS | 5 |
| 30 | SALES | CHICAGO | 6 |
| 40 | OPERATIONS | BOSTON | 0 |
+--------+------------+----------+------+
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28.列出各种工作的最低工资及从事此工作的雇员姓名
第一步:找出各种工作的最低工资
select
job,min(sal) as minsal
from
emp
group by
job;
+-----------+---------+
| job | minsal |
+-----------+---------+
| CLERK | 800.00 |
| SALESMAN | 1250.00 |
| MANAGER | 2450.00 |
| ANALYST | 3000.00 |
| PRESIDENT | 5000.00 |
+-----------+---------+
第二步:从emp表中筛选最低工资和工作岗位相对的员工
select
e.*
from
emp e
join
(select
job,min(sal) as minsal
from
emp
group by
job) t
on
e.sal=t.minsal and e.job=t.job;
+-------+--------+-----------+------+------------+---------+---------+--------+
| EMPNO | ENAME | JOB | MGR | HIREDATE | SAL | COMM | DEPTNO |
+-------+--------+-----------+------+------------+---------+---------+--------+
| 7369 | SMITH | CLERK | 7902 | 1980-12-17 | 800.00 | NULL | 20 |
| 7521 | WARD | SALESMAN | 7698 | 1981-02-22 | 1250.00 | 500.00 | 30 |
| 7654 | MARTIN | SALESMAN | 7698 | 1981-09-28 | 1250.00 | 1400.00 | 30 |
| 7782 | CLARK | MANAGER | 7839 | 1981-06-09 | 2450.00 | NULL | 10 |
| 7788 | SCOTT | ANALYST | 7566 | 1987-04-19 | 3000.00 | NULL | 20 |
| 7839 | KING | PRESIDENT | NULL | 1981-11-17 | 5000.00 | NULL | 10 |
| 7902 | FORD | ANALYST | 7566 | 1981-12-03 | 3000.00 | NULL | 20 |
+-------+--------+-----------+------+------------+---------+---------+--------+
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29.列出各个部门的 MANAGER(领导)的最低薪金
select
deptno,min(sal)
from
emp
where
job='MANAGER'
group by
deptno;
+--------+----------+
| deptno | min(sal) |
+--------+----------+
| 20 | 2975.00 |
| 30 | 2850.00 |
| 10 | 2450.00 |
+--------+----------+
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30.列出所有员工的年工资,按年薪从低到高排序
年工资=sal*12+comm*12
select
ename,(sal*12+ifnull(comm,0)*12) as incomm
from
emp
order by
incomm asc;
+--------+----------+
| ename | incomm |
+--------+----------+
| SMITH | 9600.00 |
| JAMES | 11400.00 |
| ADAMS | 13200.00 |
| MILLER | 15600.00 |
| TURNER | 18000.00 |
| WARD | 21000.00 |
| ALLEN | 22800.00 |
| CLARK | 29400.00 |
| MARTIN | 31800.00 |
| BLAKE | 34200.00 |
| JONES | 35700.00 |
| SCOTT | 36000.00 |
| FORD | 36000.00 |
| KING | 60000.00 |
+--------+----------+
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31.求出员工领导的薪水超过 3000 的员工名称与领导名称
select
e.ename,l.ename
from
emp e
join
emp l
on
e.mgr=l.empno
where
l.sal>3000;
+-------+-------+
| ename | ename |
+-------+-------+
| JONES | KING |
| BLAKE | KING |
| CLARK | KING |
+-------+-------+
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32.求出部门名称中,带’S’字符的部门员工的工资合计、部门人数
select
d.dname,ifnull(sum(e.sal),0),ifnull(count(e.ename),0)
from
dept d
left join
emp e
on
d.deptno=e.deptno
where
d.dname like '%S%'
group by
d.dname;
+------------+----------------------+--------------------------+
| dname | ifnull(sum(e.sal),0) | ifnull(count(e.ename),0) |
+------------+----------------------+--------------------------+
| RESEARCH | 10875.00 | 5 |
| SALES | 9400.00 | 6 |
| OPERATIONS | 0.00 | 0 |
+------------+----------------------+--------------------------+
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33.给任职日期超过 30 年的员工加薪 10%
update emp set sal=sal*1.1 where timestampdiff(YEAR,hiredate,now());
1
34.总结select查询:
select查询:
select
...
from
...
(join
...)
where
...
group by
..
having
...
order by
...
limit
...
执行顺序?
1.from
2.where
3.group by
4.having
5.select
6.order by
7.limit