17. Letter Combinations of a Phone Number

Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.

Example 1:

Input: digits = "23"
Output: ["ad","ae","af","bd","be","bf","cd","ce","cf"]

Example 2:

Input: digits = ""
Output: []

Example 3:

Input: digits = "2"
Output: ["a","b","c"]

Constraints:

• 0 <= digits.length <= 4
• digits[i] is a digit in the range [‘2’, ‘9’].

public class Solution {
    public List letterCombinations(String digits) {
        List result = new ArrayList();
        if(digits == null || digits.length() == 0){
            return result;
        }
        Mapchar[]> map = new HashMapchar[]>();
        map.put('2', new char[]{'a', 'b', 'c'});
        map.put('3', new char[]{'d', 'e', 'f'});
        map.put('4', new char[]{'g', 'h', 'i'});
        map.put('5', new char[]{'j', 'k', 'l'});
        map.put('6', new char[]{'m', 'n', 'o'});
        map.put('7', new char[]{'p', 'q', 'r', 's'});
        map.put('8', new char[]{'t', 'u', 'v'});
        map.put('9', new char[]{'w', 'x', 'y', 'z'});
        StringBuilder sb = new StringBuilder();
        dfs(digits, sb, map, result);
        return result;
    }
    
    public void dfs(String digits, StringBuilder sb, Mapchar[]> map, List result){
    	if(sb.length() == digits.length()){
    		result.add(sb.toString());
    		return;
    	}
    	for(char c : map.get(digits.charAt(sb.length()))){
    		sb.append(c);
    		dfs(digits, sb, map, result);
    		sb.deleteCharAt(sb.length() - 1);
    	}
    }
}