HJ18 识别有效的IP地址和掩码并进行分类统计

题目

HJ18 识别有效的IP地址和掩码并进行分类统计

思路

先将十进制带点的ip地址转成二进制序列（没有点），再直接比较。
rjust右对齐，左边补充0.
re.search(“/./.”, str) 找str中的"…", 找到第一个匹配的返回一个object，找不到返回None。

代码

import sys
import re 

def get_bin(input):
    '''
    input: 10 base with dot
    output: 01 base no bot
    '''
    str_ = ""
    for e in input.split("."):
        str_ += bin(int(e))[2:].rjust(8, "0")

    return str_
A,B,C,D,E,EIM,P = 0, 0, 0, 0, 0, 0, 0
for line in sys.stdin:
    a = line.split()[0]
    ip, m = a.split("~")
    if m == "0.0.0.0" or m == "255.255.255.255":
        EIM += 1 
        continue 
    # if ip.split(".")[0] in ("0", "127"):  # 如果写成ip.split(".")[0]=="0" or ip.split(".")[0]=="127" 不对 因为== 和 or 同等级会左右依次比较
    #     continue
    if (ip.split(".")[0]=="0") or (ip.split(".")[0]=="127"): # 加括号可以
        continue
    if re.search("01", get_bin(m)):
        EIM += 1
        continue
    bin_ip = get_bin(ip)
    if re.search(r"/./.", ip):
        EIM += 1
    elif get_bin("1.0.0.0") <= bin_ip <= get_bin("126.255.255.255"):
        A += 1
        if get_bin("10.0.0.0") <= bin_ip <= get_bin("10.255.255.255"):
            P += 1
    elif get_bin("128.0.0.0") <= bin_ip <= get_bin("191.255.255.255"):
        B += 1
        if get_bin("172.16.0.0") <= bin_ip <= get_bin("172.31.255.255"):
            P += 1
    elif get_bin("192.0.0.0") <= bin_ip <= get_bin("223.255.255.255"):
        C += 1
        if get_bin("192.168.0.0") <= bin_ip <= get_bin("192.168.255.255"):
            P += 1
    elif get_bin("224.0.0.0") <= bin_ip <= get_bin("239.255.255.255"):
        D += 1
    elif get_bin("240.0.0.0") <= bin_ip <= get_bin("255.255.255.255"):
        E += 1
print("{} {} {} {} {} {} {}".format(A,B,C,D,E,EIM,P))
    
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参考

【华为机试Python3题解】HJ18识别有效的IP地址和掩码并进行分类统计