使用powerMock处理静态方法

使用PowerMock进行单元测试
环境： jdk 1.8 junit 4
maven

引入pom

<dependency>
      <groupId>org.powermockgroupId>
      <artifactId>powermock-module-junit4artifactId>
      <version>2.0.9version>
      <scope>testscope>
dependency>
<dependency>
      <groupId>org.powermockgroupId>
      <artifactId>powermock-api-mockito2artifactId>
      <version>2.0.9version>
      <scope>testscope>
 dependency>

<dependency>
        <groupId>org.mockitogroupId>
        <artifactId>mockito-coreartifactId>
        <version>3.7.7version>
        <scope>testscope>
dependency>
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处理静态方法的单元测试：

类注解

@PrepareForTest(**静态类**.class)
@RunWith(PowerMockRunner.class)
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多个以，分隔

有返回的静态方法：

PowerMockito.mockStatic(**静态类**.class);
PowerMockito.when(T method).thenReturn(object);
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void 静态方法

PowerMockito.mockStatic(xxx.class);   
//类名，方法名，参数
PowerMockito.doNothing().when(xxx.class, "方法名", anyString());
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处理私有方法

spy被测类：
TestPowerMock powerMock= PowerMockito.spy(new TestPowerMock());

构造返回：
PowerMockito.when(powerMock, "methodName", param1, param2).thenReturn(2);
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