直接看代码,用stack栈来做,很好懂的啦!
请看”VCR“(逃~)
ACcode:
-
- #include<bits/stdc++.h>
- using namespace std;
- #define int long long
- const int N=3e6+10;
- int n,a[N],b[N];
- void solve() {
- cin>>n;
- for(int i=1; i<=n; i++) cin>>a[i];
- stack<int>st;
- for(int i=n; i>=1; i--) {
- while(!st.empty()&&a[i]>=a[st.top()]) st.pop();
- if(st.empty()) b[i]=0;
- else b[i]=st.top();
- st.push(i);
- }
- for(int i=1; i<=n; i++) cout<<b[i]<<" ";
- }
- signed main() {
- ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
- int t=1;
- //cin>>t;
- while(t--) {
- solve();
- }
- return 0;
- }
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over~