解题思路:
这题目要求将八进制数转换为十进制数。八进制数是以8为基数的数字系统,而十进制数是以10为基数的数字系统。
int()
可以直接将八进制字符串转换为十进制整数。现在,让我们使用这三种方法来实现八进制转换为十进制。
方法1: 直接计算法
def octal_to_decimal_direct(octal_number):
decimal_number = 0
power = 0
octal_number = int(octal_number)
while octal_number != 0:
last_digit = octal_number % 10
decimal_number += last_digit * (8 ** power)
power += 1
octal_number //= 10
return decimal_number
# 调用方法1进行转换
octal_number = "123" # Example octal number
result_method1 = octal_to_decimal_direct(octal_number)
print("Method 1 - Decimal representation:", result_method1)
方法2: 使用Python内置函数
int()
,将八进制字符串转换为十进制整数。def octal_to_decimal_builtin(octal_number):
return int(octal_number, 8)
# 调用方法2进行转换
octal_number = "123" # Example octal number
result_method2 = octal_to_decimal_builtin(octal_number)
print("Method 2 - Decimal representation:", result_method2)
方法3: 手动计算法
def octal_to_decimal_manual(octal_number):
decimal_number = 0
octal_number = str(octal_number) # Convert to string to access individual digits
for i in range(len(octal_number)):
digit = int(octal_number[i])
decimal_number += digit * (8 ** (len(octal_number) - i - 1))
return decimal_number
# 调用方法3进行转换
octal_number = "123" # Example octal number
result_method3 = octal_to_decimal_manual(octal_number)
print("Method 3 - Decimal representation:", result_method3)
总结和推荐: