题目链接:耍杂技的牛
#include
#include
using namespace std;
typedef pair PII;
const int N = 50010;
int n;
PII cow[N];
int main()
{
cin >> n;
for(int i = 0; i < n; i ++)
{
int w, s;
cin >> w >> s;
cow[i] = {w + s, w};
}
sort(cow, cow + n);
// sum: 每头牛上面的重量之和
int res = -2e9, sum = 0;
for(int i = 0; i < n; i ++)
{
int w = cow[i].second, s = cow[i].first - w;
res = max(res, sum - s);
sum += w;
}
cout << res << endl;
return 0;
}