链接:
题意:
选择两两相连的三个点,要求度最小
解:
什么暴力hard
实际代码:
#include
using namespace std;
int minTrioDegree(int n, vector>& edges)
{
vectorpower(n+1);
vector>mp(n+1,vector(n+1));
for(auto& edge:edges)
{
mp[edge[0]][edge[1]] = 1;
mp[edge[0]][edge[1]] = 1;
power[edge[0]]++;
power[edge[1]]++;
}
int ans=INT_MAX;
for(int i=1;i<=n;i++)
{
for(int j=i+1;j<=n;j++)
{
for(int k=j+1;k<=n;k++)
{
if(mp[i][j] && mp[i][k] && mp[j][k])
{
ans=min(ans,power[i]+power[j]+power[k]-6);
}
}
}
}
return ans==INT_MAX? -1 : ans;
}
int main()
{
int n,m;cin>>n>>m;
vector> edges;
for(int i=1;i<=m;i++)
{
int a,b;cin>>a>>b;
edges.push_back({a,b});
}
int ans=minTrioDegree(n,edges);
cout<
限制:
2 <= n <= 400
edges[i].length == 2
1 <= edges.length <= n * (n-1) / 2
1 <= ui, vi <= n
ui != vi