- 392.判断子序列
```cpp
class Solution {
public:
bool isSubsequence(string s, string t) {
vector
for (int i = 1; i <= s.size(); i++) {
for (int j = 1; j <= t.size(); j++) {
if (s[i - 1] == t[j - 1]) dp[i][j] = dp[i - 1][j - 1] + 1;
else dp[i][j] = dp[i][j - 1];
}
}
return dp[s.size()][t.size()] == s.size();
}
};
```
- 115.不同的子序列
(有一个测试案例过不了,官方题解都过不了)
```cpp
class Solution {
public:
int numDistinct(string s, string t) {
vector
for (int i = 0; i < s.size(); i++) dp[i][0] = 1;
for (int i = 1; i <= s.size(); i++) {
for (int j = 1; j <= t.size(); j++) {
if (s[i - 1] == t[j - 1]) dp[i][j] = dp[i - 1][j] + dp[i - 1][j - 1];
else dp[i][j] = dp[i - 1][j];
}
}
return dp[s.size()][t.size()];
}
};
```