Codeforces Round #835 (Div. 4) A. Medium Number

Codeforces Round #835 (Div. 4) A. Medium Number

Here are two ways to implement what’s given in the problem:

1. Take input as an array $[a_1,a_2,a_3]$, and sort it. Output the middle element.
2. Write two if-statements. The first: if $(a>b$ $and$ $a<c)$ $or$ $(a<b$ $and$ $a>c)$, output $a$. Else, if $(b>a$ $and$ $b<c)$ $or$ $(b<a$ $and$ $b>c)$, output $b$. Else, output $c$.

#include
using namespace std;

int main()
{
    int T=1;cin>>T;
    while(T--)
    {
        int a[3];
        cin>>a[0]>>a[1]>>a[2];
        sort(a,a+3);
        cout<<a[1]<<endl;
    }
    return 0;
}
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