LeetCode 阿姆斯特朗数

提取输入的正整数的每一位数字，然后进行计算

def test(N):
    temp = N
    list = []
    # 判断大于10的，应该一位数肯定是符合条件的
    while temp / 10.0 > 0:
        s = temp % 10
        list.append(s)
        temp = temp // 10
    sum = 0
    for item in list:
        sum += item ** len(list)
    if sum == N:
        return True
    else:
        return False

res = test(153)
print(res)
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def test2(N):
    strN = str(N)
    list = [int(item) for item in strN]
    sum = 0
    for item in list:
        sum += item ** len(list)
    return sum == N


res = test2(153)
print(res)
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def test2(N):
    _list = list(str(N))
    sum = 0
    for item in _list:
        sum += int(item) ** len(_list)
    return sum == N


res = test2(153)
print(res)

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11