• 3.4 Swaps


    3.4 Swaps

    Question 1

    Two companies, C and D, have the borrowing rates shown in the following table.

    CompanyFixed BorrowingFloating Borrowing
    C 10 % 10\% 10%LIBOR + 50 50 50 bps
    D 12 % 12\% 12%LIBOR + 100 100 100 bps

    According to the comparative advantage argument, what is the total potential savings for C and D if they enter into an interest rate swap?

    A. 0.5 % 0.5\% 0.5%
    B. 1.0 % 1.0\% 1.0%
    C. 1.5 % 1.5\% 1.5%
    D. 2.0 % 2.0\% 2.0%

    Answer: C
    The difference of the differences is (12% - 10%) - [LIBOR + 1% - (LIBOR + 0.5%)] = 1.5%.


    Question 2

    PE2018Q60 / PE2019Q60 / PE2020Q60 / PE2021Q60 / PE2022Q60
    An oil driller recently issued USD 250 250 250 million of fixed-rate debt at 4.0 % 4.0\% 4.0% per year to help fund a new project. It now wants to convert this debt to a floating-rate obligation using a swap. A swap desk analyst for a large investment bank that is a market maker in swaps has identified four firms interested in swapping their debt from floating-rate to fixed-rate. The following table quotes available loan rates for the oil driller and each firm:

    FirmFixed-rate(in % \% %)Floating-rate(in % \% %)
    Oil driller 4.0 4.0 4.06-month LIBOR + 1.5 + 1.5 +1.5
    Firm A 3.5 3.5 3.56-month LIBOR + 1.0 + 1.0 +1.0
    Firm B 6.0 6.0 6.06-month LIBOR + 3.0 + 3.0 +3.0
    Firm C 5.5 5.5 5.56-month LIBOR + 2.0 + 2.0 +2.0
    Firm D 4.5 4.5 4.56-month LIBOR + 2.5 + 2.5 +2.5

    A swap between the oil driller and which firm offers the greatest possible combined benefit?

    A. Firm A
    B. Firm B
    C. Firm C
    D. Firm D

    Answer: C
    Learning Objective: Describe the comparative advantage argument for the existence of interest rate swaps and evaluate some of the criticisms of this argument.

    Since the oil driller is swapping out of a fixed-rate and into a floating-rate, the larger the difference between the fixed spread and the floating spread the greater the combined benefit.

    See table below:

    FirmFixed-rateFloating-rateFixed-spreadFloating spreadPossible Benfit
    Oil driller4.01.5
    Firm A3.51.0-0.5-0.5-0.0
    Firm B6.03.02.01.50.5
    Firm C5.52.01.50.51.0
    Firm D4.52.50.51.0-0.5

    Question 3

    Firm X wants to borrow GBP at a floating interest rate, and Firm ‘I’ wants to borrow GBP at a fixed annual interest rate. The interest rates that they face are shown in the table below. What is the maximum spread a financial intermediary could get if it designs a swap making firms X and Y each better off by 20 20 20 basis points?

    FirmFixedFloating
    X4.5%6-month LIBOR + 1.5%
    Y5.5%6-month LIBOR + 2.0%

    A. 5 5 5 basis points
    B. 10 10 10 basis points
    C. 15 15 15 basis points
    D. 20 20 20 basis mints


    Question 4

    PE2018Q78 / PE2019Q78 / PE2020Q78 / PE2021Q78 / PE2022Q78
    A financial institution entered into a 4-year currency swap contract with a French industrial company. Under the terms of the swap, the financial institution receives interest at 3 % 3\% 3% per year in EUR and pays interest at 2 % 2\% 2% per year in USD. The principal amounts are EUR 50 50 50 million and USD 60 60 60 million, and interest payments are exchanged once a year. Suppose that it is exactly one year before expiration of the swap contract and just in time for the year 3 3 3 cash flow payments and receipts when the exchange rate is USD 1.044 1.044 1.044 per EUR 1 1 1, the 1-year French risk-free rate is 3.0 % 3.0\% 3.0% and the 1-year US Treasury rate is 2.0 % 2.0\% 2.0%. Assuming continuous compounding, what is the value of the swap to the financial institution at the end of year 3 3 3?

    A. USD − 7.603 -7.603 7.603 million
    B. USD − 7.456 -7.456 7.456 million
    C. USD − 7.068 -7.068 7.068 million
    D. USD − 6.921 -6.921 6.921 million

    Answer: B
    Learning Objective: Explain the mechanics of a currency swap and compute its cash flows.

    Step 1: calculate the forward exchange rates as at the end of year 3 3 3:

    1 year forward exchange rate (USD per EUR):
    F = S × e ( r u s d – r e u r ) × T = 1.044 × e ( 0.02 – 0.03 ) × 1 = 1.0336 F = S \times e^{(r_{usd} – r_{eur})\times T} = 1.044 \times e^{(0.02 – 0.03)\times 1} = 1.0336 F=S×e(rusdreur)×T=1.044×e(0.02–0.03)×1=1.0336

    Step 2: calculate the expected cash flows as at year 3:
    Receipts:
    Year 3: EUR 50 × 0.03 = 1.5    million 50 \times 0.03 = 1.5 \;\text{million} 50×0.03=1.5million
    Year 4: EUR 50 × 0.03 + 50 = 51.5    million 50 \times 0.03 + 50 = 51.5 \;\text{million} 50×0.03+50=51.5million
    Payments:
    Year 3: USD 60 × 0.02 = 1.2    million 60 \times 0.02 = 1.2 \;\text{million} 60×0.02=1.2million
    Year 4: USD 60 × 0.02 + 60 = 61.2    million 60 \times 0.02 + 60 = 61.2 \;\text{million} 60×0.02+60=61.2million

    Step 3: convert the EUR cash flows into base currency, i.e. USD:
    Receipts:
    Year 3: USD 1.5 × 1.0440 = 1.566    million 1.5 \times 1.0440 = 1.566 \;\text{million} 1.5×1.0440=1.566million
    Year 4: USD 51.5 × 1.0336 = 53.2304    million 51.5\times 1.0336 = 53.2304 \;\text{million} 51.5×1.0336=53.2304million

    Step 4: Net the cash flows per year:
    Year 3: USD 1.566 − 1.2 = 0.366    million 1.566 - 1.2 = 0.366 \;\text{million} 1.5661.2=0.366million
    Year 4: USD 53.230 − 61.2 = − 7.969    million 53.230 - 61.2 = -7.969 \;\text{million} 53.23061.2=7.969million

    Step 5: discount to year 3 and sum the cash flows in USD:
    Year 3: Present value USD 0.366    million 0.366\;\text{million} 0.366million
    Year 4: Present value USD − 7.969 × e − 0.02 × 1 = − 7.811    million -7.969\times e^{-0.02 \times 1} = -7.811 \;\text{million} 7.969×e0.02×1=7.811million

    Net value to the financial institution 0.366 − 7.811 = − 7.456    million 0.366 - 7.811 = -7.456\;\text{million} 0.3667.811=7.456million

    A is incorrect. USD − 7.603 -7.603 7.603 million uses the appropriate exchange rates but does not discount back to year 3 3 3.

    C is incorrect. USD − 7.068 -7.068 7.068 million uses the current USD per EUR rate (USD 1.044 1.044 1.044) to convert the EUR cash flows and does not discount back to year 3 3 3.

    D is incorrect. USD − 6.921 -6.921 6.921 million uses the current USD per EUR rate (USD 1.044 1.044 1.044) to convert the EUR cash flows; however, it does discount back to year 3 3 3.


    Question 5

    PE2018Q34 / PE2019Q34 / PE2020Q34 / PE2022Q34 / PE2022PSQ24 / PE2022Q34
    Savers Bancorp entered into a 2-year interest rate swap on August 9, 2014, in which it received a 4.00 % 4.00\% 4.00% fixed rate and paid LIBOR plus 1.20 % 1.20\% 1.20% on a notional amount of USD 6.5 6.5 6.5 million. Payments were to be made every 6 months. The table below displays the actual annual 6-month LIBOR rates over the 2-year period:

    DateAug 9, 2014Feb 9, 2015Aug 9, 2015Feb 9, 2016Aug 9, 2016
    LIBOR3.11%1.76%0.84%0.39%0.58%

    Assuming no default, how much did Savers Bancorp receive on August 9, 2016?

    A. USD 72,150
    B. USD 78,325
    C. USD 117,325
    D. USD 156,650

    Answer: B
    Learning Objective: Explain the mechanics of a plain vanilla interest rate swap and compute its cash flows.

    The proper interest rate to use is the 6-month LIBOR rate at February 9, 2016, since it is the 6-month LIBOR that will yield the payoff on August 9, 2016.

    Therefore, the net settlement amount on August 9, 2016 is as follows:
    Savers Bancorp receives: 6 , 500 , 000 × 4.00 % × 0.5 6,500,000\times4.00\%\times0.5 6,500,000×4.00%×0.5, or USD 130 , 000 130,000 130,000
    Savers Bancorp pays: 6 , 500 , 000 × ( 0.39 % + 1.20 % ) × 0.5 6,500,000\times(0.39\%+1.20\%)\times0.5 6,500,000×(0.39%+1.20%)×0.5, or USD 51 , 675 51,675 51,675

    Therefore, Savers Bancorp would receive the difference of USD 78,325,


    Question 6

    Consider a USD 1 1 1 million notional swap that pays a floating rate based on 6 6 6-month LIBOR and receives a 6 % 6\% 6% fixed rate semiannually. The swap has a remaining life of 15 15 15 months with pay dates at 3 3 3, 9 9 9 and 15 15 15 months. Spot LIBOR rates are as following: 3 3 3 months at 5.4 % 5.4\% 5.4%; 9 9 9 months at 5.6 % 5.6\% 5.6%; and 15 15 15 months at 5.8 % 5.8\% 5.8%. The LIBOR at the last payment date was 5.0 % 5.0\% 5.0%. Calculate the value of the swap to the fixed-rate receiver using the bond methodology.

    A. USD 6 , 077 6,077 6,077
    B. USD − 6 , 077 -6,077 6,077
    C. USD − 5 , 077 -5,077 5,077
    D. USD 5 , 077 5,077 5,077

    Answer:D


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  • 原文地址:https://blog.csdn.net/agoldminer/article/details/127644512