Two companies, C and D, have the borrowing rates shown in the following table.
Company | Fixed Borrowing | Floating Borrowing |
---|---|---|
C | 10 % 10\% 10% | LIBOR + 50 50 50 bps |
D | 12 % 12\% 12% | LIBOR + 100 100 100 bps |
According to the comparative advantage argument, what is the total potential savings for C and D if they enter into an interest rate swap?
A.
0.5
%
0.5\%
0.5%
B.
1.0
%
1.0\%
1.0%
C.
1.5
%
1.5\%
1.5%
D.
2.0
%
2.0\%
2.0%
Answer: C
The difference of the differences is (12% - 10%) - [LIBOR + 1% - (LIBOR + 0.5%)] = 1.5%.
PE2018Q60 / PE2019Q60 / PE2020Q60 / PE2021Q60 / PE2022Q60
An oil driller recently issued USD
250
250
250 million of fixed-rate debt at
4.0
%
4.0\%
4.0% per year to help fund a new project. It now wants to convert this debt to a floating-rate obligation using a swap. A swap desk analyst for a large investment bank that is a market maker in swaps has identified four firms interested in swapping their debt from floating-rate to fixed-rate. The following table quotes available loan rates for the oil driller and each firm:
Firm | Fixed-rate(in % \% %) | Floating-rate(in % \% %) |
---|---|---|
Oil driller | 4.0 4.0 4.0 | 6-month LIBOR + 1.5 + 1.5 +1.5 |
Firm A | 3.5 3.5 3.5 | 6-month LIBOR + 1.0 + 1.0 +1.0 |
Firm B | 6.0 6.0 6.0 | 6-month LIBOR + 3.0 + 3.0 +3.0 |
Firm C | 5.5 5.5 5.5 | 6-month LIBOR + 2.0 + 2.0 +2.0 |
Firm D | 4.5 4.5 4.5 | 6-month LIBOR + 2.5 + 2.5 +2.5 |
A swap between the oil driller and which firm offers the greatest possible combined benefit?
A. Firm A
B. Firm B
C. Firm C
D. Firm D
Answer: C
Learning Objective: Describe the comparative advantage argument for the existence of interest rate swaps and evaluate some of the criticisms of this argument.
Since the oil driller is swapping out of a fixed-rate and into a floating-rate, the larger the difference between the fixed spread and the floating spread the greater the combined benefit.
See table below:
Firm | Fixed-rate | Floating-rate | Fixed-spread | Floating spread | Possible Benfit |
---|---|---|---|---|---|
Oil driller | 4.0 | 1.5 | |||
Firm A | 3.5 | 1.0 | -0.5 | -0.5 | -0.0 |
Firm B | 6.0 | 3.0 | 2.0 | 1.5 | 0.5 |
Firm C | 5.5 | 2.0 | 1.5 | 0.5 | 1.0 |
Firm D | 4.5 | 2.5 | 0.5 | 1.0 | -0.5 |
Firm X wants to borrow GBP at a floating interest rate, and Firm ‘I’ wants to borrow GBP at a fixed annual interest rate. The interest rates that they face are shown in the table below. What is the maximum spread a financial intermediary could get if it designs a swap making firms X and Y each better off by 20 20 20 basis points?
Firm | Fixed | Floating |
---|---|---|
X | 4.5% | 6-month LIBOR + 1.5% |
Y | 5.5% | 6-month LIBOR + 2.0% |
A.
5
5
5 basis points
B.
10
10
10 basis points
C.
15
15
15 basis points
D.
20
20
20 basis mints
PE2018Q78 / PE2019Q78 / PE2020Q78 / PE2021Q78 / PE2022Q78
A financial institution entered into a 4-year currency swap contract with a French industrial company. Under the terms of the swap, the financial institution receives interest at
3
%
3\%
3% per year in EUR and pays interest at
2
%
2\%
2% per year in USD. The principal amounts are EUR
50
50
50 million and USD
60
60
60 million, and interest payments are exchanged once a year. Suppose that it is exactly one year before expiration of the swap contract and just in time for the year
3
3
3 cash flow payments and receipts when the exchange rate is USD
1.044
1.044
1.044 per EUR
1
1
1, the 1-year French risk-free rate is
3.0
%
3.0\%
3.0% and the 1-year US Treasury rate is
2.0
%
2.0\%
2.0%. Assuming continuous compounding, what is the value of the swap to the financial institution at the end of year
3
3
3?
A. USD
−
7.603
-7.603
−7.603 million
B. USD
−
7.456
-7.456
−7.456 million
C. USD
−
7.068
-7.068
−7.068 million
D. USD
−
6.921
-6.921
−6.921 million
Answer: B
Learning Objective: Explain the mechanics of a currency swap and compute its cash flows.
Step 1: calculate the forward exchange rates as at the end of year 3 3 3:
1 year forward exchange rate (USD per EUR):
F
=
S
×
e
(
r
u
s
d
–
r
e
u
r
)
×
T
=
1.044
×
e
(
0.02
–
0.03
)
×
1
=
1.0336
F = S \times e^{(r_{usd} – r_{eur})\times T} = 1.044 \times e^{(0.02 – 0.03)\times 1} = 1.0336
F=S×e(rusd–reur)×T=1.044×e(0.02–0.03)×1=1.0336
Step 2: calculate the expected cash flows as at year 3:
Receipts:
Year 3: EUR
50
×
0.03
=
1.5
million
50 \times 0.03 = 1.5 \;\text{million}
50×0.03=1.5million
Year 4: EUR
50
×
0.03
+
50
=
51.5
million
50 \times 0.03 + 50 = 51.5 \;\text{million}
50×0.03+50=51.5million
Payments:
Year 3: USD
60
×
0.02
=
1.2
million
60 \times 0.02 = 1.2 \;\text{million}
60×0.02=1.2million
Year 4: USD
60
×
0.02
+
60
=
61.2
million
60 \times 0.02 + 60 = 61.2 \;\text{million}
60×0.02+60=61.2million
Step 3: convert the EUR cash flows into base currency, i.e. USD:
Receipts:
Year 3: USD
1.5
×
1.0440
=
1.566
million
1.5 \times 1.0440 = 1.566 \;\text{million}
1.5×1.0440=1.566million
Year 4: USD
51.5
×
1.0336
=
53.2304
million
51.5\times 1.0336 = 53.2304 \;\text{million}
51.5×1.0336=53.2304million
Step 4: Net the cash flows per year:
Year 3: USD
1.566
−
1.2
=
0.366
million
1.566 - 1.2 = 0.366 \;\text{million}
1.566−1.2=0.366million
Year 4: USD
53.230
−
61.2
=
−
7.969
million
53.230 - 61.2 = -7.969 \;\text{million}
53.230−61.2=−7.969million
Step 5: discount to year 3 and sum the cash flows in USD:
Year 3: Present value USD
0.366
million
0.366\;\text{million}
0.366million
Year 4: Present value USD
−
7.969
×
e
−
0.02
×
1
=
−
7.811
million
-7.969\times e^{-0.02 \times 1} = -7.811 \;\text{million}
−7.969×e−0.02×1=−7.811million
Net value to the financial institution 0.366 − 7.811 = − 7.456 million 0.366 - 7.811 = -7.456\;\text{million} 0.366−7.811=−7.456million
A is incorrect. USD − 7.603 -7.603 −7.603 million uses the appropriate exchange rates but does not discount back to year 3 3 3.
C is incorrect. USD − 7.068 -7.068 −7.068 million uses the current USD per EUR rate (USD 1.044 1.044 1.044) to convert the EUR cash flows and does not discount back to year 3 3 3.
D is incorrect. USD − 6.921 -6.921 −6.921 million uses the current USD per EUR rate (USD 1.044 1.044 1.044) to convert the EUR cash flows; however, it does discount back to year 3 3 3.
PE2018Q34 / PE2019Q34 / PE2020Q34 / PE2022Q34 / PE2022PSQ24 / PE2022Q34
Savers Bancorp entered into a 2-year interest rate swap on August 9, 2014, in which it received a
4.00
%
4.00\%
4.00% fixed rate and paid LIBOR plus
1.20
%
1.20\%
1.20% on a notional amount of USD
6.5
6.5
6.5 million. Payments were to be made every 6 months. The table below displays the actual annual 6-month LIBOR rates over the 2-year period:
Date | Aug 9, 2014 | Feb 9, 2015 | Aug 9, 2015 | Feb 9, 2016 | Aug 9, 2016 |
---|---|---|---|---|---|
LIBOR | 3.11% | 1.76% | 0.84% | 0.39% | 0.58% |
Assuming no default, how much did Savers Bancorp receive on August 9, 2016?
A. USD 72,150
B. USD 78,325
C. USD 117,325
D. USD 156,650
Answer: B
Learning Objective: Explain the mechanics of a plain vanilla interest rate swap and compute its cash flows.
The proper interest rate to use is the 6-month LIBOR rate at February 9, 2016, since it is the 6-month LIBOR that will yield the payoff on August 9, 2016.
Therefore, the net settlement amount on August 9, 2016 is as follows:
Savers Bancorp receives:
6
,
500
,
000
×
4.00
%
×
0.5
6,500,000\times4.00\%\times0.5
6,500,000×4.00%×0.5, or USD
130
,
000
130,000
130,000
Savers Bancorp pays:
6
,
500
,
000
×
(
0.39
%
+
1.20
%
)
×
0.5
6,500,000\times(0.39\%+1.20\%)\times0.5
6,500,000×(0.39%+1.20%)×0.5, or USD
51
,
675
51,675
51,675
Therefore, Savers Bancorp would receive the difference of USD 78,325,
Consider a USD 1 1 1 million notional swap that pays a floating rate based on 6 6 6-month LIBOR and receives a 6 % 6\% 6% fixed rate semiannually. The swap has a remaining life of 15 15 15 months with pay dates at 3 3 3, 9 9 9 and 15 15 15 months. Spot LIBOR rates are as following: 3 3 3 months at 5.4 % 5.4\% 5.4%; 9 9 9 months at 5.6 % 5.6\% 5.6%; and 15 15 15 months at 5.8 % 5.8\% 5.8%. The LIBOR at the last payment date was 5.0 % 5.0\% 5.0%. Calculate the value of the swap to the fixed-rate receiver using the bond methodology.
A. USD
6
,
077
6,077
6,077
B. USD
−
6
,
077
-6,077
−6,077
C. USD
−
5
,
077
-5,077
−5,077
D. USD
5
,
077
5,077
5,077
Answer:D