编写一个程序,通过填充空格来解决数独问题。
数独的解法需 遵循如下规则:
数字 1-9 在每一行只能出现一次。
数字 1-9 在每一列只能出现一次。
数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)
数独部分空格内已填入了数字,空白格用 '.' 表示。
示例 1:
输入:board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]
输出:[["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]]
解释:输入的数独如上图所示,唯一有效的解决方案如下所示:
提示:
board.length == 9
board[i].length == 9
board[i][j] 是一位数字或者 '.'
题目数据 保证 输入数独仅有一个解
来源:力扣(LeetCode)
链接:https://leetcode.cn/problems/sudoku-solver
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c++代码
- class Solution {
- private:
- bool finish;
- bool rowArr[9][10],colArr[9][10],areaArr[9][10];
- public:
- void init(vector
char >>& board){//用于初始化三个arr数组 - memset(rowArr,false,sizeof(rowArr));
- memset(colArr,false,sizeof(colArr));
- memset(areaArr,false,sizeof(areaArr));
- for(int i=0;i<9;i++){
- for(int j=0;j<9;j++){
- if(board[i][j]!='.'){
- rowArr[i][board[i][j]-48]=true;
- colArr[j][board[i][j]-48]=true;
- areaArr[getAreaIndex(i,j)][board[i][j]-48]=true;
- }
- }
- }
- }
- int getAreaIndex(int row,int col){
- return 3*(row/3)+col/3;
- }
- void dfs(vector
char >>& board,int index){ - if(index==81){
- finish=true;
- return;
- }
- int row=index/9;
- int col=index%9;
- char val=board[row][col];
- if(val!='.'){
- dfs(board,index+1);
- }else{
- for(int num=1;num<10;++num){
- bool rowTemp=rowArr[row][num];
- bool colTemp=colArr[col][num];
- bool areaTemp=areaArr[getAreaIndex(row,col)][num];
- if(!rowTemp&&!colTemp&&!areaTemp){
- rowArr[row][num]=true;
- colArr[col][num]=true;
- areaArr[getAreaIndex(row,col)][num]=true;
- board[row][col]=(char)(num+48);
- dfs(board,index+1);
- if(finish){
- return;
- }
- rowArr[row][num]=rowTemp;
- colArr[col][num]=colTemp;
- areaArr[getAreaIndex(row,col)][num]=areaTemp;
- board[row][col]='.';
- }
- }
-
- }
- }
- void solveSudoku(vector
char >>& board) { - init(board);
- finish=false;
- dfs(board,0);
- }
- };