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目录
/**
* 根据用户id查询用户信息
* @param id
* @return
*/
User getUserById(@Param("id") int id);
- <select id="getUserById" resultType="User">
- select * from t_user where id=#{id};
- </select>
- @Test
- public void test() {
- SqlSessionUtils sqlSessionUtils = new SqlSessionUtils();
- SqlSession sqlSession = sqlSessionUtils.getSqlSession();
- SelectMapper mapper = sqlSession.getMapper(SelectMapper.class);
- User user = mapper.getUserById(2);
- System.out.println(user);
-
- }
表:

查询结果:

假如,我把后面的条件删除,会发生什么情况呢?


org.apache.ibatis.exceptions.TooManyResultsException: Expected one result (or null) to be returned by selectOne(), but found: 3
当查询的数据为多条时,不能使用实体类作为返回值,否则会抛出异常
TooManyResultsException;但是若查询的数据只有一条,可以使用实体类或集合作为返回值
/**
* 查询所有用户信息
* @return
*/
List
getUserList();
- <select id="getAllUser" resultType="User">
- select * from t_user;
- </select>
测试类:
- @Test
- public void test2(){
- SqlSessionUtils sqlSessionUtils = new SqlSessionUtils();
- SqlSession sqlSession = sqlSessionUtils.getSqlSession();
- SelectMapper mapper = sqlSession.getMapper(SelectMapper.class);
- List
allUser = mapper.getAllUser(); - allUser.forEach(System.out::println);
-
- }
查询结果:

/*** 查询用户的总记录数* @return* 在 MyBatis 中,对于 Java 中常用的类型都设置了类型别名* 例如: java.lang.Integer-->int|integer* 例如: int-->_int|_integer* 例如: Map-->map,List-->list*/int getCount ();
- <select id="getCount" resultType="java.lang.Integer">
- select count(id) from t_user;
- </select>
测试类:
- @Test
- public void test3(){
- SqlSessionUtils sqlSessionUtils = new SqlSessionUtils();
- SqlSession sqlSession = sqlSessionUtils.getSqlSession();
- SelectMapper mapper = sqlSession.getMapper(SelectMapper.class);
- Integer count = mapper.getCount();
- System.out.println(count);
-
- }
表:
查询结果:

/*** 根据用户 id 查询用户信息为 map 集合* @param id* @return*/Map < String , Object > getUserToMap ( @Param ( "id" ) int id );
- <!--Map
getUserToMap(@Param("id") int id);--> -
- <select id="getUserToMap" resultType="map">
- select * from t_user where id = #{id}
- </select>
测试类:
- @Test
- public void test4(){
- SqlSessionUtils sqlSessionUtils = new SqlSessionUtils();
- SqlSession sqlSession = sqlSessionUtils.getSqlSession();
- SelectMapper mapper = sqlSession.getMapper(SelectMapper.class);
- Map
map = mapper.getUserToMap(4); - System.out.println(map);
- }

①方式一
/*** 查询所有用户信息为 map 集合* @return* 将表中的数据以 map 集合的方式查询,一条数据对应一个 map ;若有多条数据,就会产生多个 map 集合,此时可以将这些 map 放在一个 list 集合中获取*/List < Map < String , Object >> getAllUserToMap ();
- <!--Map
getAllUserToMap();--> - <select id="getAllUserToMap" resultType="map">
- select * from t_user
- </select>
测试类:
- @Test
- public void test5(){
- SqlSessionUtils sqlSessionUtils = new SqlSessionUtils();
- SqlSession sqlSession = sqlSessionUtils.getSqlSession();
- SelectMapper mapper = sqlSession.getMapper(SelectMapper.class);
- List
- System.out.println(allUserToMap);
- }

/*** 查询所有用户信息为 map 集合* @return* 将表中的数据以 map 集合的方式查询,一条数据对应一个 map ;若有多条数据,就会产生多个 map 集合,并且最终要以一个 map 的方式返回数据,此时需要通过 @MapKey 注解设置 map 集合的键,值是每条数据所对应的map 集合*/@MapKey ( "id" )Map < String , Object > getAllUserToMap ();
-
- <select id="getAllUserToMap" resultType="map">
- select * from t_user
- </select>
测试类:
- @Test
- public void test6(){
- SqlSessionUtils sqlSessionUtils = new SqlSessionUtils();
- SqlSession sqlSession = sqlSessionUtils.getSqlSession();
- SelectMapper mapper = sqlSession.getMapper(SelectMapper.class);
- Map
allUserToMap = mapper.getAllUserToMap(); - System.out.println(allUserToMap);
-
- }
运行结果:
{1={password=123, sex=男, id=1, age=23, email=11111@qq.com, username=张三},
2={password=root, sex=女, id=2, age=23, email=11111@qq.com, username=root},
3={password=789123, sex=女, id=3, age=28, email=9090889@qq.com, username=小王}, 4={password=1234567, sex=男, id=4, age=34, email=1487418@qq.com, username=小李}}