参考一下刘金琨的《先进PID控制》这本书。
例子：被控对象yout(k)=a(k)yout(k-1)/(1+yout(k-1)^2)+u(k_1)其中a（k）=1.2(1-0.8e^(-0.1k))输入信号：rin（k）=1.0和rin（k）=sin（2t）%BPbasedPIDControlclearall;closeall;xite=0.25;//学习速率alfa=0.05;//惯性系数S=1;%SignaltypeIN=4;H=5;Out=3;%NNStructureifS==1%StepSignalwi=[-0.6394-0.2696-0.3756-0.7023;-0.8603-0.2013-0.5024-0.2596;-1.07490.5543-1.6820-0.5437;-0.3625-0.0724-0.6463-0.2859;0.14250.0279-0.5406-0.7660];%wi=0.50*rands(H,IN);wi_1=wi;wi_2=wi;wi_3=wi;wo=[0.75760.26160.5820-0.1416-0.1325;-0.11460.29490.83520.22050.4508;0.72010.45660.76720.49620.3632];%wo=0.50*rands(Out,H);wo_1=wo;wo_2=wo;wo_3=wo;endifS==2%SineSignalwi=[-0.28460.2193-0.5097-1.0668;-0.7484-0.1210-0.47080.0988;-0.71760.8297-1.60000.2049;-0.08580.1925-0.63460.0347;0.43580.2369-0.4564-0.1324];%wi=0.50*rands(H,IN);w