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∑i=1kai(n)=1,n=0,1,2,⋯pij⩾0,i,j=1,2,⋯,k∑j=1kpij=1,i=1,2,⋯,k" role="presentation" style="position: relative;">∑ki=1ai(n)=1,pij⩾0,∑kj=1pij=1,n=0,1,2,⋯i,j=1,2,⋯,ki=1,2,⋯,k