1069 The Black Hole of Numbers

题目描述
知识点： 模拟
思路： 按照题目意思模拟即可，注意没有4位数字的需要补零进行处理排序。

#include
#include
#include
#include
using namespace std;
string my_sort(string n,int flag){
    vector<char> s;
    for(auto i : n)
        s.push_back(i);
    sort(s.begin(),s.end());
    string res = "";
    if(flag == 0){
        for(auto i : s)
            res += i;
    }else{
        for(int i = s.size()-1;i >= 0;i--)
            res += s[i];
    }
    return res;
}
int main(){
    string n;
    cin>>n;
    while(n.length() < 4)
        n = '0' + n;    
    int s1 = stoi(my_sort(n,0));
    int s2 = stoi(my_sort(n,1));
    printf("%04d - %04d = %04d\n",s2,s1,s2-s1);
    while(s2 - s1 != 6174 && s2 - s1 != 0){
        int c = s2-s1;
        string y = to_string(c);
        while(y.length() < 4)
            y = '0' + y;
        s1 = stoi(my_sort(y,0));
        s2 = stoi(my_sort(y,1));
        printf("%04d - %04d = %04d\n",s2,s1,s2-s1);
    }
    return 0;
}
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