给你一个下标从 0 开始、大小为 n x n 的整数矩阵 grid ,返回满足 Ri 行和 Cj 列相等的行列对 (Ri, Cj) 的数目。
如果行和列以相同的顺序包含相同的元素(即相等的数组),则认为二者是相等的。
示例 1:

输入:grid = [[3,2,1],[1,7,6],[2,7,7]]
输出:1
解释:存在一对相等行列对:

输入:grid = [[3,1,2,2],[1,4,4,5],[2,4,2,2],[2,4,2,2]]
输出:3
解释:存在三对相等行列对:
提示:
n == grid.length == grid[i].length
1 <= n <= 200
1 <= grid[i][j] <= 105
public int equalPairs(int[][] grid) {
Map<String, Integer> row = new HashMap<>();
Map<String, Integer> col = new HashMap<>();
for (int i = 0; i < grid.length; i++) {
StringBuilder rowsb = new StringBuilder();
StringBuilder colsb = new StringBuilder();
for (int j = 0; j < grid[0].length; j++) {
rowsb.append(grid[i][j]).append(" ");
colsb.append(grid[j][i]).append(" ");
}
String rows = rowsb.toString();
row.put(rows,row.getOrDefault(rows,0)+1);
String cols = colsb.toString();
col.put(cols,col.getOrDefault(cols,0)+1);
}
int sum=0;
for (String s : row.keySet()) {
sum+=row.get(s)*col.getOrDefault(s,0);
}
return sum;
}

func equalPairs(grid [][]int) int {
row := make(map[string]int, 0)
col := make(map[string]int, 0)
for i, v := range grid {
rowsb := make([]string, 0)
colsb := make([]string, 0)
for j,_ := range v {
rowsb = append(rowsb,string(grid[i][j]))
colsb = append(colsb,string(grid[j][i]))
}
rows := strings.Join(rowsb, " ")
cols := strings.Join(colsb, " ")
row[rows]++
col[cols]++
}
sum:=0
for k, v := range row {
temp,ok:=col[k]
if ok{
sum+=v*temp
}
}
return sum
}
