B - Dungeon Master

You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or down. You cannot move diagonally and the maze is surrounded by solid rock on all sides.

Is an escape possible? If yes, how long will it take?

Input

The input consists of a number of dungeons. Each dungeon description starts with a line containing three integers L, R and C (all limited to 30 in size).
L is the number of levels making up the dungeon.
R and C are the number of rows and columns making up the plan of each level.
Then there will follow L blocks of R lines each containing C characters. Each character describes one cell of the dungeon. A cell full of rock is indicated by a '#' and empty cells are represented by a '.'. Your starting position is indicated by 'S' and the exit by the letter 'E'. There's a single blank line after each level. Input is terminated by three zeroes for L, R and C.

Output

Each maze generates one line of output. If it is possible to reach the exit, print a line of the form

Escaped in x minute(s).

where x is replaced by the shortest time it takes to escape.
If it is not possible to escape, print the line

Trapped!

Sample

3 4 5
S....
.###.
.##..
###.#

#####
#####
##.##
##...

#####
#####
#.###
####E

1 3 3
S##
#E#
###

0 0 0

Escaped in 11 minute(s).
Trapped!

 人写麻了，

#include<bits/stdc++.h>
 
using namespace std;
typedef long long ll;
#define IOS ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int way[6][3]={{1,0,0},{-1,0,0},{0,1,0},{0,-1,0},{0,0,1},{0,0,-1},};
//六个方向
int l,r,c;
//长宽高
const int maxx=32;
//注意数组范围
char dungeon[maxx][maxx][maxx];
//地牢
bool visited[maxx][maxx][maxx];
//判断是否访问过
typedef struct node{
    int x,y,z;
    int step;
}node;
//结构体定义坐标，步数
int start_x,start_y,start_z;
//起点
int end_x,end_y,end_z;
//终点
bool check(int x,int y,int z){
    if(x<0||x>=l||y<0||y>=r||z<0||z>=c) return true;
    //越界情况
    else if(visited[x][y][z]) return true;
    //是否走过该位置
    else if(dungeon[x][y][z]=='#') return true;
    //是否有障碍物
    return false;
}
int bfs(){
    queue<node> q;
    node t,head;
    //head存队头元素
    head.x=start_x;head.y=start_y;head.z=start_z;
    head.step=0;
    q.push(head);
    while(!q.empty()){
        head=q.front();
        if(head.x==end_x&&head.y==end_y&&head.z==end_z) return head.step;
        q.pop();
        for(int i=0;i<6;i++){
            t.x=head.x+way[i][0];
            t.y=head.y+way[i][1];
            t.z=head.z+way[i][2];
            if(check(t.x,t.y,t.z)) continue;
            t.step=head.step+1;
            visited[t.x][t.y][t.z]=true;
            q.push(t);
        }
    }
    return 0;
}
int main(){
    IOS;
    while(cin>>l>>r>>c){
        if(l==0&&r==0&&c==0) break;
        for(int i=0;i<l;i++){
            for(int j=0;j<r;j++){
                cin>>dungeon[i][j];
                for(int k=0;k<c;k++){
                    if(dungeon[i][j][k]=='S'){
                        start_x=i;
                        start_y=j;
                        start_z=k;
                    }
                    else if(dungeon[i][j][k]=='E'){
                        end_x=i;
                        end_y=j;
                        end_z=k;
                    }
                }
            }
        }
        memset(visited,false,sizeof(visited));
        int res=bfs();
        if(res) cout<<"Escaped in "<<res<<" minute(s)."<<endl;
        else cout<<"Trapped!"<<endl;
    }
}