目录



内容呈现黑白色,猜测可能为二进制数字,且一共104(0-103)张图片,我们假设白色为0,黑色为1,每8个一组进行ASCII解码。
将图片转换成二进制数字
01100110 01101100 01100001 01100111 01111011 01000110 01110101 01001110 01011111 01100111 01101001 01000110 01111101
二进制转换成ASCII地址:https://coding.tools/cn/binary-to-text

flag{FuN_giF}

c8e9aca0c6f2e5f3e8c4efe7a1a0d4e8e5a0e6ece1e7a0e9f3baa0e8eafae3f9e4eafae2eae4e3eaebfaebe3f5e7e9f3e4e3e8eaf9eaf3e2e4e6f2


根据观察我们发现,得到的这一串很明显是128-255部分的。
于是我们考虑对得到的ascii码进行取余操作
- flag = ''
-
- s='c8e9aca0c6f2e5f3e8c4efe7a1a0d4e8e5a0e6ece1e7a0e9f3baa0e8eafae3f9e4eafae2eae4e3eaebfaebe3f5e7e9f3e4e3e8eaf9eaf3e2e4e6f2'
-
- l = len(s)//2
-
- for i in range(l):
-
- flag += chr(int(s[i*2:(i+1)*2], 16) % 128)
-
- print(flag, end='')
python运行网址:https://c.runoob.com/compile/9/

flag{hjzcydjzbjdcjkzkcugisdchjyjsbdfr}

- ┌──(root㉿kali)-[~/Desktop]
-
- └─# mkdir xctf-misc
-
-
- ┌──(root㉿kali)-[~/Desktop]
-
- └─# ls
-
- Burp_Suite_Pro_v2020.1.1 f1fc23f5c743425d9e0073887c846d23 vulhub xctf-misc
-
-
- ┌──(root㉿kali)-[~/Desktop]
-
- └─# mount f1fc23f5c743425d9e0073887c846d23 xctf-misc/
-
-
- ┌──(root㉿kali)-[~/Desktop]
-
- └─# cd xctf-misc
-
-
- ┌──(root㉿kali)-[~/Desktop/xctf-misc]
-
- └─# ls
-
- 02CdWGSxGPX.bin 0wDq5 3J 7H7geLlS5 8RxQG4bvd h i jj LO0J8 m9V0lIaElz Nv orcA Q Raf3SYj sdb.cramfs T
-
- 0GY1l 0Xs 44aAm 8A2MFawD4 FinD H imgLDPt4BY KxEQM lost+found MiU o oSx2p qkCN8 rhZE1LZ6g sn TFGVOSwYd.txt
-
- 0h3a5 1 4A 8DQFirm0D fm H2Zj8FNbu ix1EMRHRpIc2 LG6F LvuGM Mnuc O7avZhikgKgbF OT QmUY1d Ruc9 SPaK8l2sYN
-
- 0l 2X 6JR3 8HhWfV9nK1 g hdi7 j6uLMX Lh lWIRfzP n o8 poiuy7Xdb QQY3sF63w RZTOGd SrZznhSAj
-
- 0qsd 3 6wUaZE1vbsW 8nwg gtj hYuPvID jE LlC6Z0zrgy.bin m NgzQPW OOoOs px6u r scripts t
-
-
-
- ┌──(root㉿kali)-[~/Desktop/xctf-misc]
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- └─# find / -name flag.txt
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- /root/Desktop/xctf-misc/O7avZhikgKgbF/flag.txt
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- ┌──(root㉿kali)-[~/Desktop/xctf-misc]
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- └─# cd O7avZhikgKgbF
-
-
- ┌──(root㉿kali)-[~/Desktop/xctf-misc/O7avZhikgKgbF]
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- └─# ls
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- flag.txt
-
-
- ┌──(root㉿kali)-[~/Desktop/xctf-misc/O7avZhikgKgbF]
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- └─# cat flag.txt
-
- ZmxhZ3tzYWpiY2lienNrampjbmJoc2J2Y2pianN6Y3N6Ymt6an0=
-
-

flag{sajbcibzskjjcnbhsbvcjbjszcszbkzj}