• 数据分析实际案例之:pandas在泰坦尼特号乘客数据中的使用


    简介

    1912年4月15日,号称永不沉没的泰坦尼克号因为和冰山相撞沉没了。因为没有足够的救援设备,2224个乘客中有1502个乘客不幸遇难。事故已经发生了,但是我们可以从泰坦尼克号中的历史数据中发现一些数据规律吗?今天本文将会带领大家灵活的使用pandas来进行数据分析。

    泰坦尼特号乘客数据

    我们从kaggle官网中下载了部分泰坦尼特号的乘客数据,主要包含下面几个字段:

    变量名 含义 取值
    survival 是否生还 0 = No, 1 = Yes
    pclass 船票的级别 1 = 1st, 2 = 2nd, 3 = 3rd
    sex 性别
    Age 年龄
    sibsp 配偶信息
    parch 父母或者子女信息
    ticket 船票编码
    fare 船费
    cabin 客舱编号
    embarked 登录的港口 C = Cherbourg, Q = Queenstown, S = Southampton

    下载下来的文件是一个csv文件。接下来我们来看一下怎么使用pandas来对其进行数据分析。

    使用pandas对数据进行分析

    引入依赖包

    本文主要使用pandas和matplotlib,所以需要首先进行下面的通用设置:

    from numpy.random import randn
    import numpy as np
    np.random.seed(123)
    import os
    import matplotlib.pyplot as plt
    import pandas as pd
    plt.rc('figure', figsize=(10, 6))
    np.set_printoptions(precision=4)
    pd.options.display.max_rows = 20
    

    读取和分析数据

    pandas提供了一个read_csv方法可以很方便的读取一个csv数据,并将其转换为DataFrame:

    path = '../data/titanic.csv'
    df = pd.read_csv(path)
    df
    

    我们看下读入的数据:

    PassengerId Pclass Name Sex Age SibSp Parch Ticket Fare Cabin Embarked
    0 892 3 Kelly, Mr. James male 34.5 0 0 330911 7.8292 NaN Q
    1 893 3 Wilkes, Mrs. James (Ellen Needs) female 47.0 1 0 363272 7.0000 NaN S
    2 894 2 Myles, Mr. Thomas Francis male 62.0 0 0 240276 9.6875 NaN Q
    3 895 3 Wirz, Mr. Albert male 27.0 0 0 315154 8.6625 NaN S
    4 896 3 Hirvonen, Mrs. Alexander (Helga E Lindqvist) female 22.0 1 1 3101298 12.2875 NaN S
    5 897 3 Svensson, Mr. Johan Cervin male 14.0 0 0 7538 9.2250 NaN S
    6 898 3 Connolly, Miss. Kate female 30.0 0 0 330972 7.6292 NaN Q
    7 899 2 Caldwell, Mr. Albert Francis male 26.0 1 1 248738 29.0000 NaN S
    8 900 3 Abrahim, Mrs. Joseph (Sophie Halaut Easu) female 18.0 0 0 2657 7.2292 NaN C
    9 901 3 Davies, Mr. John Samuel male 21.0 2 0 A/4 48871 24.1500 NaN S
    ... ... ... ... ... ... ... ... ... ... ... ...
    408 1300 3 Riordan, Miss. Johanna Hannah"" female NaN 0 0 334915 7.7208 NaN Q
    409 1301 3 Peacock, Miss. Treasteall female 3.0 1 1 SOTON/O.Q. 3101315 13.7750 NaN S
    410 1302 3 Naughton, Miss. Hannah female NaN 0 0 365237 7.7500 NaN Q
    411 1303 1 Minahan, Mrs. William Edward (Lillian E Thorpe) female 37.0 1 0 19928 90.0000 C78 Q
    412 1304 3 Henriksson, Miss. Jenny Lovisa female 28.0 0 0 347086 7.7750 NaN S
    413 1305 3 Spector, Mr. Woolf male NaN 0 0 A.5. 3236 8.0500 NaN S
    414 1306 1 Oliva y Ocana, Dona. Fermina female 39.0 0 0 PC 17758 108.9000 C105 C
    415 1307 3 Saether, Mr. Simon Sivertsen male 38.5 0 0 SOTON/O.Q. 3101262 7.2500 NaN S
    416 1308 3 Ware, Mr. Frederick male NaN 0 0 359309 8.0500 NaN S
    417 1309 3 Peter, Master. Michael J male NaN 1 1 2668 22.3583 NaN C

    418 rows × 11 columns

    调用df的describe方法可以查看基本的统计信息:

    PassengerId Pclass Age SibSp Parch Fare
    count 418.000000 418.000000 332.000000 418.000000 418.000000 417.000000
    mean 1100.500000 2.265550 30.272590 0.447368 0.392344 35.627188
    std 120.810458 0.841838 14.181209 0.896760 0.981429 55.907576
    min 892.000000 1.000000 0.170000 0.000000 0.000000 0.000000
    25% 996.250000 1.000000 21.000000 0.000000 0.000000 7.895800
    50% 1100.500000 3.000000 27.000000 0.000000 0.000000 14.454200
    75% 1204.750000 3.000000 39.000000 1.000000 0.000000 31.500000
    max 1309.000000 3.000000 76.000000 8.000000 9.000000 512.329200

    如果要想查看乘客登录的港口,可以这样选择:

    df['Embarked'][:10]
    
    0    Q
    1    S
    2    Q
    3    S
    4    S
    5    S
    6    Q
    7    S
    8    C
    9    S
    Name: Embarked, dtype: object
    

    使用value_counts 可以对其进行统计:

    embark_counts=df['Embarked'].value_counts()
    embark_counts[:10]
    
    S    270
    C    102
    Q     46
    Name: Embarked, dtype: int64
    

    从结果可以看出,从S港口登录的乘客有270个,从C港口登录的乘客有102个,从Q港口登录的乘客有46个。

    同样的,我们可以统计一下age信息:

    age_counts=df['Age'].value_counts()
    age_counts.head(10)
    

    前10位的年龄如下:

    24.0    17
    21.0    17
    22.0    16
    30.0    15
    18.0    13
    27.0    12
    26.0    12
    25.0    11
    23.0    11
    29.0    10
    Name: Age, dtype: int64
    

    计算一下年龄的平均数:

    df['Age'].mean()
    
    30.272590361445783
    

    实际上有些数据是没有年龄的,我们可以使用平均数对其填充:

    clean_age1 = df['Age'].fillna(df['Age'].mean())
    clean_age1.value_counts()
    

    可以看出平均数是30.27,个数是86。

    30.27259    86
    24.00000    17
    21.00000    17
    22.00000    16
    30.00000    15
    18.00000    13
    26.00000    12
    27.00000    12
    25.00000    11
    23.00000    11
                ..
    36.50000     1
    40.50000     1
    11.50000     1
    34.00000     1
    15.00000     1
    7.00000      1
    60.50000     1
    26.50000     1
    76.00000     1
    34.50000     1
    Name: Age, Length: 80, dtype: int64
    

    使用平均数来作为年龄可能不是一个好主意,还有一种办法就是丢弃平均数:

    clean_age2=df['Age'].dropna()
    clean_age2
    age_counts = clean_age2.value_counts()
    ageset=age_counts.head(10)
    ageset
    
    24.0    17
    21.0    17
    22.0    16
    30.0    15
    18.0    13
    27.0    12
    26.0    12
    25.0    11
    23.0    11
    29.0    10
    Name: Age, dtype: int64
    

    图形化表示和矩阵转换

    图形化对于数据分析非常有帮助,我们对于上面得出的前10名的age使用柱状图来表示:

    import seaborn as sns
    sns.barplot(x=ageset.index, y=ageset.values)
    

    接下来我们来做一个复杂的矩阵变换,我们先来过滤掉age和sex都为空的数据:

    cframe=df[df.Age.notnull() & df.Sex.notnull()]
    cframe
    
    PassengerId Pclass Name Sex Age SibSp Parch Ticket Fare Cabin Embarked
    0 892 3 Kelly, Mr. James male 34.5 0 0 330911 7.8292 NaN Q
    1 893 3 Wilkes, Mrs. James (Ellen Needs) female 47.0 1 0 363272 7.0000 NaN S
    2 894 2 Myles, Mr. Thomas Francis male 62.0 0 0 240276 9.6875 NaN Q
    3 895 3 Wirz, Mr. Albert male 27.0 0 0 315154 8.6625 NaN S
    4 896 3 Hirvonen, Mrs. Alexander (Helga E Lindqvist) female 22.0 1 1 3101298 12.2875 NaN S
    5 897 3 Svensson, Mr. Johan Cervin male 14.0 0 0 7538 9.2250 NaN S
    6 898 3 Connolly, Miss. Kate female 30.0 0 0 330972 7.6292 NaN Q
    7 899 2 Caldwell, Mr. Albert Francis male 26.0 1 1 248738 29.0000 NaN S
    8 900 3 Abrahim, Mrs. Joseph (Sophie Halaut Easu) female 18.0 0 0 2657 7.2292 NaN C
    9 901 3 Davies, Mr. John Samuel male 21.0 2 0 A/4 48871 24.1500 NaN S
    ... ... ... ... ... ... ... ... ... ... ... ...
    403 1295 1 Carrau, Mr. Jose Pedro male 17.0 0 0 113059 47.1000 NaN S
    404 1296 1 Frauenthal, Mr. Isaac Gerald male 43.0 1 0 17765 27.7208 D40 C
    405 1297 2 Nourney, Mr. Alfred (Baron von Drachstedt")" male 20.0 0 0 SC/PARIS 2166 13.8625 D38 C
    406 1298 2 Ware, Mr. William Jeffery male 23.0 1 0 28666 10.5000 NaN S
    407 1299 1 Widener, Mr. George Dunton male 50.0 1 1 113503 211.5000 C80 C
    409 1301 3 Peacock, Miss. Treasteall female 3.0 1 1 SOTON/O.Q. 3101315 13.7750 NaN S
    411 1303 1 Minahan, Mrs. William Edward (Lillian E Thorpe) female 37.0 1 0 19928 90.0000 C78 Q
    412 1304 3 Henriksson, Miss. Jenny Lovisa female 28.0 0 0 347086 7.7750 NaN S
    414 1306 1 Oliva y Ocana, Dona. Fermina female 39.0 0 0 PC 17758 108.9000 C105 C
    415 1307 3 Saether, Mr. Simon Sivertsen male 38.5 0 0 SOTON/O.Q. 3101262 7.2500 NaN S

    332 rows × 11 columns

    接下来使用groupby对age和sex进行分组:

    by_sex_age = cframe.groupby(['Age', 'Sex'])
    by_sex_age.size()
    
    Age    Sex   
    0.17   female    1
    0.33   male      1
    0.75   male      1
    0.83   male      1
    0.92   female    1
    1.00   female    3
    2.00   female    1
           male      1
    3.00   female    1
    5.00   male      1
                    ..
    60.00  female    3
    60.50  male      1
    61.00  male      2
    62.00  male      1
    63.00  female    1
           male      1
    64.00  female    2
           male      1
    67.00  male      1
    76.00  female    1
    Length: 115, dtype: int64
    

    使用unstack将Sex的列数据变成行:

    Sex female male
    Age
    0.17 1.0 0.0
    0.33 0.0 1.0
    0.75 0.0 1.0
    0.83 0.0 1.0
    0.92 1.0 0.0
    1.00 3.0 0.0
    2.00 1.0 1.0
    3.00 1.0 0.0
    5.00 0.0 1.0
    6.00 0.0 3.0
    ... ... ...
    58.00 1.0 0.0
    59.00 1.0 0.0
    60.00 3.0 0.0
    60.50 0.0 1.0
    61.00 0.0 2.0
    62.00 0.0 1.0
    63.00 1.0 1.0
    64.00 2.0 1.0
    67.00 0.0 1.0
    76.00 1.0 0.0

    79 rows × 2 columns

    我们把同样age的人数加起来,然后使用argsort进行排序,得到排序过后的index:

    indexer = agg_counts.sum(1).argsort()
    indexer.tail(10)
    
    Age
    58.0    37
    59.0    31
    60.0    29
    60.5    32
    61.0    34
    62.0    22
    63.0    38
    64.0    27
    67.0    26
    76.0    30
    dtype: int64
    

    从agg_counts中取出最后的10个,也就是最大的10个:

    count_subset = agg_counts.take(indexer.tail(10))
    count_subset=count_subset.tail(10)
    count_subset
    
    Sex female male
    Age
    29.0 5.0 5.0
    25.0 1.0 10.0
    23.0 5.0 6.0
    26.0 4.0 8.0
    27.0 4.0 8.0
    18.0 7.0 6.0
    30.0 6.0 9.0
    22.0 10.0 6.0
    21.0 3.0 14.0
    24.0 5.0 12.0

    上面的操作可以简化为下面的代码:

    agg_counts.sum(1).nlargest(10)
    
    Age
    21.0    17.0
    24.0    17.0
    22.0    16.0
    30.0    15.0
    18.0    13.0
    26.0    12.0
    27.0    12.0
    23.0    11.0
    25.0    11.0
    29.0    10.0
    dtype: float64
    

    将count_subset 进行stack操作,方便后面的画图:

    stack_subset = count_subset.stack()
    stack_subset
    
    Age   Sex   
    29.0  female     5.0
          male       5.0
    25.0  female     1.0
          male      10.0
    23.0  female     5.0
          male       6.0
    26.0  female     4.0
          male       8.0
    27.0  female     4.0
          male       8.0
    18.0  female     7.0
          male       6.0
    30.0  female     6.0
          male       9.0
    22.0  female    10.0
          male       6.0
    21.0  female     3.0
          male      14.0
    24.0  female     5.0
          male      12.0
    dtype: float64
    
    stack_subset.name = 'total'
    stack_subset = stack_subset.reset_index()
    stack_subset
    
    Age Sex total
    0 29.0 female 5.0
    1 29.0 male 5.0
    2 25.0 female 1.0
    3 25.0 male 10.0
    4 23.0 female 5.0
    5 23.0 male 6.0
    6 26.0 female 4.0
    7 26.0 male 8.0
    8 27.0 female 4.0
    9 27.0 male 8.0
    10 18.0 female 7.0
    11 18.0 male 6.0
    12 30.0 female 6.0
    13 30.0 male 9.0
    14 22.0 female 10.0
    15 22.0 male 6.0
    16 21.0 female 3.0
    17 21.0 male 14.0
    18 24.0 female 5.0
    19 24.0 male 12.0

    作图如下:

    sns.barplot(x='total', y='Age', hue='Sex',  data=stack_subset)
    

    本文例子可以参考: https://github.com/ddean2009/learn-ai/

    本文已收录于 http://www.flydean.com/01-pandas-titanic/

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  • 原文地址:https://www.cnblogs.com/flydean/p/15931247.html