Word Game

题目链接：Problem - C - Codeforces

解题思路：

用map存字母和出现的次数，然后遍历三个字母数组，如果map值为1，则加三分，为2加1分，否则不加分。

下面是c++代码：

#include
#include
using namespace std;
int main()
{
    int n, num, a1 = 0, a2 = 0, a3 = 0;
    cin >> n;
    while (n != 0) {
        a1 = 0, a2 = 0, a3 = 0;
        mapint> mp;
        cin >> num;
        string* arr1 = new string[num];
        string* arr2 = new string[num];
        string* arr3 = new string[num];
        for (int i = 0; i < num; i++) {
            cin >> arr1[i];
            mp[arr1[i]]++;
        }for (int i = 0; i < num; i++) {
            cin >> arr2[i];
            mp[arr2[i]]++;
        }for (int i = 0; i < num; i++) {
            cin >> arr3[i];
            mp[arr3[i]]++;
        }
        for (int i = 0; i < num; i++) {
            if (mp[arr1[i]] == 1) {
                a1 += 3;
            }
            else if (mp[arr1[i]] == 2) {
                a1 += 1;
            }
        }for (int i = 0; i < num; i++) {
            if (mp[arr2[i]] == 1) {
                a2 += 3;
            }
            else if (mp[arr2[i]] == 2) {
                a2 += 1;
            }
        }for (int i = 0; i < num; i++) {
            if (mp[arr3[i]] == 1) {
                a3 += 3;
            }
            else if (mp[arr3[i]] == 2) {
                a3 += 1;
            }
        }
        cout << a1 << " " << a2 << " " << a3 << endl;
        n--;
    }
    return 0;
}