Bellman-Ford(G, w, s) for each vertex v 属于 V[G] d[v] = 无穷大 p[v] = NIL d[s] = 0 for i = 1 to |V[G]| - 1 relax(u, v, w) for each edge(u, v)属于E[G] if d[v] > d[u] + w(u, v) return false return true
UVa11090 Going in Cycle!!
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