语法练习：diff21

语法练习：diff21

题目：diff21

Given an int n, return the absolute difference between n and 21, except return double the absolute difference if n is over 21.

diff21(19) → 2
diff21(10) → 11
diff21(21) → 0

我的解答：

def diff21(n):
  if n > 21:
    return 2 * (n - 21
1
2